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Karo-lina-s [1.5K]
3 years ago
9

Algebra help pls <3

Mathematics
1 answer:
Liono4ka [1.6K]3 years ago
3 0
B is right:
because it is -2 will make it 0 so it is two unit to the left.

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Which two fractions have a sum of - 7/24
Feliz [49]
The two fractions that added together give you a sum of -7/24 are 1/24+-8/24= -7/24
6 0
3 years ago
What is the value of the right rectangular prism
storchak [24]
Hello!

To find the area of a rectangular prism you do 2(lw + lh + wh)

Put in the values

2(9 * 2 + 9 * 6 + 2 * 6)

2(18 + 54 + 12)

2(84)

2 * 84 = 168

The answer is 168 cubic inches

Hope this helps!

6 0
3 years ago
Find x so that x, X +2, X'+3 are the first three terms of a geometric sequence. Then find the 5" term of the
velikii [3]

Answer:

The fifth term is -1/4.

Step-by-step explanation:

We know that the first three terms of the geometric sequence is <em>x, x</em> + 2, and <em>x </em>+ 3.

So, our first term is <em>x</em>.

Then our second term will be our first term multiplied by the common ratio <em>r</em>. So:

x+2=xr

And our third term will be our first term multiplied by the common ratio <em>r</em> twice. Therefore:

x+3=xr^2

Solve for <em>x</em>. From the second term, we can divide both sides by <em>x: </em>

\displaystyle r=\frac{x+2}{x}

Substitute this into the third equation:

\displaystyle x+3=x\Big(\frac{x+2}{x}\Big)^2

Square:

\displaystyle x+3 = x\Big( \frac{(x+2)^2}{x^2} \Big)

Simplify:

\displaystyle x+3=\frac{(x+2)^2}{x}

We can multiply both sides by <em>x: </em>

x(x+3)=(x+2)^2

Expand:

x^2+3x=x^2+4x+4

Isolate the <em>x: </em>

-x=4

Hence, our first term is:

x=-4

Then our common ratio <em>r</em> is:

\displaystyle r=\frac{(-4)+2}{-4}=\frac{-2}{-4}=\frac{1}{2}

So, our first term is -4 and our common ratio is 1/2.

Then our sequence will be -4, -2, -1, -1/2, -1/4.

You can verify that the first three terms indeed follow the pattern of <em>x</em>, <em>x</em> + 2, and <em>x</em> + 3.

So, our fifth term is -1/4.

4 0
3 years ago
23 times 536 what is the proodsuct to that number
Nikolay [14]
   
23 × 536 = 12328
==============



4 0
3 years ago
5.
ANTONII [103]

The greatest possible number of club members is 7

<em><u>Solution:</u></em>

Given that, local readers’ club has a set of 49 hardback books and a set of 21 paperbacks

Each set can be divided equally among the club members

To find the greatest possible number of club members, we have to find the greatest common factor of 49 and 21

The greatest number that is a factor of two (or more) other numbers.

When we find all the factors of two or more numbers, and some factors are the same ("common"), then the largest of those common factors is the Greatest Common Factor.

<em><u>Greatest common factor of 49 and 21:</u></em>

The factors of 21 are: 1, 3, 7, 21

The factors of 49 are: 1, 7, 49

Then the greatest common factor is 7

Thus, the greatest possible number of club members is 7

7 0
3 years ago
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