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Mashcka [7]
3 years ago
13

Kenya plans to make a down payment plus monthly payment in order to buy a motorcycle. At one dealer she would pay $2,500 down an

d $150 each month. At another dealer, she would pay $3,000 down and $125 each month. After how many month would the total amount paid be the same for both dealers? What would that the amount be?
Mathematics
2 answers:
s2008m [1.1K]3 years ago
7 0
First, create an equation for the price of the car for both dealerships:

Dealership A:   y = 150x + 2500
Dealership B:   y = 125x + 3000

where y is the total cost of the car and x is the number of months that have passed.

You know that y is equal to "150x + 2500" AND y is equal to "125x + 3000," so "150x + 2500" must be equal to "125x + 3000"

150x+2500=125x+3000

Now, just solve for x to find the number of months at which the total amount paid would be the same for both dealers:

150x+2500=125x+3000\\150x-125x+2500=3000\\25x+2500=3000\\25x=3000-2500\\25x=500\\25x/25=500/25\\x=20

So, after 20 months, the price of the car at both dealerships is the same. To find that price, just plug in 20 for x in one of the equations (because x was the number of months):

y=150x+2500\\y=150(20)=2500\\y=3000+2500\\y=5500

So, the car costs the same after 20 months, $5500 at either dealership.
ozzi3 years ago
7 0
After 21 months Kenya would pay the same amount at both dealers. The amount would be $5,500.
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Answer:

<em>l = w + 3cm</em>

<em>l = w + 3cmp = 2l + 2w = 58cm</em>

<em>l = w + 3cmp = 2l + 2w = 58cm </em>

<em>l = w + 3cmp = 2l + 2w = 58cm Solve by substitution:</em>

<em>l = w + 3cmp = 2l + 2w = 58cm Solve by substitution:2l + 2w = 58 ⇒ 2(w + 3) + 2w = 58</em>

<em>l = w + 3cmp = 2l + 2w = 58cm Solve by substitution:2l + 2w = 58 ⇒ 2(w + 3) + 2w = 58⇒ 2w + 6 + 2w = 4w + 6 = 58</em>

<em>l = w + 3cmp = 2l + 2w = 58cm Solve by substitution:2l + 2w = 58 ⇒ 2(w + 3) + 2w = 58⇒ 2w + 6 + 2w = 4w + 6 = 58⇒ 4w = 52 ⇒ w = 13</em>

<em>l = w + 3cmp = 2l + 2w = 58cm Solve by substitution:2l + 2w = 58 ⇒ 2(w + 3) + 2w = 58⇒ 2w + 6 + 2w = 4w + 6 = 58⇒ 4w = 52 ⇒ w = 13 </em>

<em>l = w + 3cmp = 2l + 2w = 58cm Solve by substitution:2l + 2w = 58 ⇒ 2(w + 3) + 2w = 58⇒ 2w + 6 + 2w = 4w + 6 = 58⇒ 4w = 52 ⇒ w = 13 Plug back in:</em>

<em>l = w + 3cmp = 2l + 2w = 58cm Solve by substitution:2l + 2w = 58 ⇒ 2(w + 3) + 2w = 58⇒ 2w + 6 + 2w = 4w + 6 = 58⇒ 4w = 52 ⇒ w = 13 Plug back in:l = (13cm) + 3cm = 16cm</em>

<em>l = w + 3cmp = 2l + 2w = 58cm Solve by substitution:2l + 2w = 58 ⇒ 2(w + 3) + 2w = 58⇒ 2w + 6 + 2w = 4w + 6 = 58⇒ 4w = 52 ⇒ w = 13 Plug back in:l = (13cm) + 3cm = 16cmStep-by-step explanation:</em>

I hope this helps you.

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