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zimovet [89]
3 years ago
9

8 lb 1 oz − 3 lb 6 oz

Mathematics
2 answers:
Serggg [28]3 years ago
8 0

Answer:

4.6875 is the answer

Step-by-step explanation:

ladessa [460]3 years ago
6 0

First, lets put both into just ounces. (1lb = 16oz.)

8lb. 1oz. = 129oz.

3lb. 6oz. = 54oz.

Second, subtract.

129 - 54 = 75

Third, put into pounds and ounces.

75oz. = 4lb. 11oz.

_______

Best Regards,

Wolfyy :)

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Translate question into an equation, let x be unknown number 6.4 is 90% of what number?
lisov135 [29]
1 \% = \frac{1}{100}\\ \\90 \% * x =6.4  \\ \\\frac{90}{100}x=6.4  \\ \\\frac{9 }{10 }x=6.4 \ \ *(\frac{10}{9})\\ \\x= 6.4 *\frac{10}{9}\\ \\x=\frac{64}{9}\\ \\x = 7\frac{1}{9}
8 0
3 years ago
Read 2 more answers
Ed’s rental charges a flat fee of $5 plus $2 per hour to rent a pair of skates.
zavuch27 [327]
Flat doesn't change
2 changes with x
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5 0
3 years ago
First to completly answer will be marked brainliest if you give a random answer just to get points you will be reported
HACTEHA [7]

Answer:

Pi: Irrational

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225: Rational

0.167: Irrational  <--- fourth one

Step-by-step explanation:

Not sure about the 4th one, but the others are good :)

7 0
3 years ago
A cooler contains fifteen bottles of sports drink: eight lemon-lime flavored and seven orange flavored
dem82 [27]

Answer:

Mutually exclusive,

P(\text{Lemon-lime or orange})=\frac{2}{3}

Step-by-step explanation:

Please consider the complete question:

Determine if the scenario involves mutually exclusive or overlapping events. Then find the  probability.

A cooler contains twelve bottles of sports  drink: four lemon-lime flavored, four  orange flavored, and four fruit-punch  flavored. You randomly grab a bottle. It  is a lemon-lime or an orange.

Let us find probability of finding one lemon lime drink.

P(\text{Lemon-lime})=\frac{\text{Number of lemon lime drinks}}{\text{Total drinks}}

P(\text{Lemon-lime})=\frac{4}{12}

P(\text{Lemon-lime})=\frac{1}{3}

Let us find probability of finding one orange drink.

P(\text{Orange})=\frac{\text{Number of orange drinks}}{\text{Total drinks}}

P(\text{Orange})=\frac{4}{12}

P(\text{Orange})=\frac{1}{3}

Since probability of choosing a lemon lime doesn't effect probability of choosing orange drink, therefore, both events are mutually exclusive.

We know that probability of two mutually exclusive events is equal to the sum of both probabilities.

P(\text{Lemon-lime or orange})=P(\text{Lemon-lime})+P(\text{Orange})

P(\text{Lemon-lime or orange})=\frac{1}{3}+\frac{1}{3}

P(\text{Lemon-lime or orange})=\frac{1+1}{3}

P(\text{Lemon-lime or orange})=\frac{2}{3}

Therefore, the probability of choosing a lemon lime or orange is \frac{2}{3}.

8 0
3 years ago
If you have a 20 ounce bottle and you pour 3 1/4 out how much is left
IrinaVladis [17]
1/4 is 5oz, so you have 15 oz left 
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6 0
3 years ago
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