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lbvjy [14]
3 years ago
11

The network services and facilities that users interact with are provided by

Computers and Technology
1 answer:
docker41 [41]3 years ago
6 0
<span>The network services and facilities that users interact with are provided by authentication.</span>
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The instruction format of a computer is given by one indirect bit, opcode bits, register address bits, immediate operand bits an
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Following are the answer to this question:

Explanation:

A)

The memory size is 1 Giga Bytes which is equal to 2^{30}

\texttt{Number of address bits    \ \ \ \ \ \ \ \ \ \ \ \ \ \            Number of addresses}\\\\ \ \ \ \ 30  \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \  \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \                                 2^{30}= 1073741824

B) \texttt{I \ \ \ Opcode  \ \ \ Register address \ \ \  Immediate operand \ \ \    Memory address}\\\\\\\textt{1 \ bit  \  \ \ \ \ \ 128  \ \ \ \ \ \ \ \ \ \ \ \ \ \ \    2 \ bits   \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \   24 \ bits  \ \ \ \ \ \ \ \ \ \ \ \ \ \ \  \ \ \ \ \ \ \ \ \           30 \ bits}\\\\\\            = 2^7 \\\\ = 7 \ bits

calculating the register Bits:

= 64-(1+7+24+30)\\\\=64 -62\ \  bits\\\\= 2\ \ bits\\

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Immediate value size while merging the additional benefit with the address field:

= 2^{24} + 2^{30}\\\\= 2^{54}\\\\\texttt{Range before combining(-,+) 24 bits   \ \ \ \ \ \       Range after combining( -,+)54bits}\\\\                         \textt{-2^{12} from + (2^{12}-1)   \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \                                    -2^{27} from + (2^{27}- 1)}

= \frac{24}{2} = 12\\\\= \frac{54}{2} = 27

The range is accomplished by dividing the bits by 2 into the two sides of the o and the number is one short to 0.

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