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larisa [96]
3 years ago
5

A scientist collected four water samples from local ponds. Each sample was the same size and he collected 2.6 liters in all. Wha

t was the volume of each water sample?
Mathematics
1 answer:
Temka [501]3 years ago
3 0

Answer: 0.65 Liters

Steps:

Divide 2.6/4 to get 0.65 Liters

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What is radius???????
xz_007 [3.2K]

A radius of a circle or sphere is any of the line segments from its center to its perimeter, and in more modern usage, it is also their length. Set up the formula for the area of a circle. The formula is A = π r 2 it equals the area of the circle, and r equals the radius.

Solve for the radius.

Plug the area into the formula.

Divide the area by.

Take the square root.

8 0
3 years ago
Which of these problem types cannot be solved using the law of sines
timama [110]

Answer: The correct option are B, C and D.

Explanation:

The law of sine states that,

\frac{\sin A}{a} =\frac{\sin B}{b}=\frac{\sin C}{c}

Where A, B, C are interior angles of the triangle and a, b, c are sides opposite sides of these angles respectively as shown in below figure. Only AAS or SSA types problems can be solved by using Law of sine.

Since we need the combination of two sides and one angle or two angles and one side.

In option A, the two consecutive angles are known and a side which makes the second angle with base side is known, therefore the first angle is opposite to the given side, so the law of sine can be used for AAS problems.

Therefore, option A is incorrect.

In option B a side is known and two inclined angle on that line are known. But to use Law of sine we want the line and angle which in not inclined on that line, therefore the ASA problem can not be solved by Law of sine and the option B is correct.

In option C two sides and their inclined angle is known. But to use Law of sine we want the side and angle which in not inclined on that line, therefore the SAS problem can not be solved by Law of sine and the option C is correct.

In  option D three sides are given but any angle is not given, therefore the SSS problem can not be solved by Law of sine and the option D is correct.

4 0
3 years ago
Please help!! i’ll give brainliest!
Flauer [41]

Answer:

I dont really understand the question but I think its -7.

3 0
3 years ago
Read 2 more answers
PLEASE HELP LAST TWO QUESTIONS, I USED ALL MY POINTS TO POST THIS PLEASE PLEASE PLEASE HELP VERY IMPORTANT
Radda [10]
<span>10.
if we were to subsitute the points and graph the equation we would notice that the shape is the same for both: a 45 degree angle line that goes upleft and up right
the graph of y=|x| looks like a right angle corner that is facing up that is ballancing on the point (0,0)
the graph of y=|x|-4 is the same except that the graph is shifter 4 units to the right ie. the point ofo the graph/rightangle is on point (4,0)




14.
slope intercept form which is y=mx+b
m=slope b=y intercept
m=4/3
y=4/3x+b
one given solution/point is (9,-1)
one solution is x=9 and y=-1 so subsitute and solve fo b
-1=4/3(9)+b
-1=36/3+b
-1=12+b
subtract 12 from both sides
-11=b
the equation si y=4/3x-11
see which one converts to the correct form
after trial and error we find that y-1=4/3(x-9) is the answer
</span>
8 0
3 years ago
During the first 13 weeks of the television season, the Saturday evening 8:00 p.m. to 9:00 p.m. audience proportions were record
SpyIntel [72]

Part 1: Do not reject H0. There has not been a significant change in the viewing audience proportions.(The above conclusion holds as the p-value is greater than the significance level of 0.05)

Part 2:

H0:  

Ha:  

Part 3: The test statistic is given as 3.0081.

Part 4: The p-value is given as  0.39037

Step-by-step explanation:

As per the data

Part 2

H0:  

Ha:  

Part 3

As per the sample is of 300 homes, the expected values are given as

ABC=p(ABC)*300=0.30*300=90

CBS=p(CBS)*300=0.27*300=81

NBC=p(NBC)*300=0.26*300=78

IND=p(IND)*300=0.17*300=51

Now the values actually are given as

ABC=94

CBS=71

NBC=88

IND=47

So the test static is given as

So the test statistic is given as 3.0081.

Part 4

Now the degree of freedoms are given as 4-1=3

and chi square  is given as 3.0081 so for α = 0.05 , the p-value is given as  0.39037

Part 1.

As the value of p in part 4 is greater than the value of α = 0.05, thus Do not reject H0. There has not been a significant change in the viewing audience proportions.(The above conclusion holds as the p-value is greater than the significance level of 0.05)

4 0
3 years ago
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