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DochEvi [55]
3 years ago
9

The polygons below are similar. Find the value of z.

Mathematics
2 answers:
Solnce55 [7]3 years ago
4 0
The value of z is 8.

The two polygons are similar. Every length value for the polygon on the right is 2 units smaller than on the left. So, FG is 6, whereas BC is 8. Z is 8, whereas on the left is was 10. etc.
Nana76 [90]3 years ago
3 0

Answer:

z=\frac{15}{2}=7.5

Step-by-step explanation:

If the two polygons are similar it means their corresponding angles are congruent and the measures of their corresponding sides are proportional.

If the sides are proportional we can construct a relationship between them like this:

\frac{AB}{EF}=\frac{AD}{EH}=\frac{BC}{FG}=\frac{DC}{HG}

Using this relationships we can solve for z, more especifically if we use:

\frac{BC}{FG}=\frac{DC}{HG}

where:

BC=8\\FG=6\\DC=10\\HG=z

we replace the values:

\frac{8}{6}=\frac{10}{z}

we solve for z

z=\frac{10*6}{8}\\z=\frac{15}{2}\\ z=7.5

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A right triangle is a triangle that has a right angle of 90 degrees. In this exercise, we have two of this type of triangles. To solve this problem, we will apply some properties of triangles, so:


1. Which step can be used to prove that triangle EFG is also a right triangle?

To prove this, we need to use Pythagorean Theorem. So, for triangle EGF, if the formula:

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We need to prove that:

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From trigonometry, we know that:

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3. Prove that the sum of a and b is greater than c.

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Applying the same reasoning as in 2:

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This inequality is always true. So, the statement has been proved.


4. Prove that triangles are congruent by SSS property and hence angle EGF is equal to angle KML.


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5. Prove that the ratio of EF and KL is greater than 1 and hence the triangles are similar by AA postulate.


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