Answer:
The average value of the function on the given interval 6.5.
Step-by-step explanation:
Consider the given function is

We need to find the average value of the function on the given interval [1,13].


The average value of the function f(x) on [a,b] is

Average value of the function on the given interval [1,13] is

![Average=\dfrac{1}{12}[\dfrac{x^2}{2}-0.5x]^{13}_{1}](https://tex.z-dn.net/?f=Average%3D%5Cdfrac%7B1%7D%7B12%7D%5B%5Cdfrac%7Bx%5E2%7D%7B2%7D-0.5x%5D%5E%7B13%7D_%7B1%7D)
![Average=\dfrac{1}{12}[\dfrac{(13)^2}{2}-0.5(13)-(\dfrac{(1)^2}{2}-0.5(1))]](https://tex.z-dn.net/?f=Average%3D%5Cdfrac%7B1%7D%7B12%7D%5B%5Cdfrac%7B%2813%29%5E2%7D%7B2%7D-0.5%2813%29-%28%5Cdfrac%7B%281%29%5E2%7D%7B2%7D-0.5%281%29%29%5D)
![Average=\dfrac{1}{12}[78-0]](https://tex.z-dn.net/?f=Average%3D%5Cdfrac%7B1%7D%7B12%7D%5B78-0%5D)

Therefore, the average value of the function on the given interval 6.5.
A? 4? i think that might be it
(5x-20) - median of a trapezoid <span>
</span>
2(5x-20) = 2x+6 + 4x+2
10x - 40 = 6x + 8
10x - 6x = 8 + 40
4x = 48
x = 48 : 4
x = 12