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Mariana [72]
4 years ago
7

I need help. Please

Mathematics
2 answers:
zubka84 [21]4 years ago
5 0

Answer:

Answer is A.

Step-by-step explanation:

If you take the current cords of 'C' and add the cords it gives you: (4.5,-6.5). You end out with (3.5,-9,2). Hope this helps!

zlopas [31]4 years ago
3 0

I think the answer is A.

Hope this helps.

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Meep says meep so what's the meep of the meep
Alex17521 [72]

Answer: ok so meep is gunna meep to the meep power of meep and 6 more meeps

Step-by-step explanation:

i got it right when i looked it up lol

6 0
3 years ago
FIND THE AREA (LEAVE EXPLANATION)
VladimirAG [237]

Answer:

20 yd²

Step-by-step explanation:

lets do the big one

4 x (6-2) = 4 x 4 = 16 yd²

2 x (4-2) = 2x2 = 4 yd²

16 yd² + 4 yd² = 20 yd²

Another way

Find the area of the figure if it was a rectangle

4 x 6 = 24 yd²

then subtract 2 x 2 = 24 yd² - 4 yd² = 20 yd²

4 0
3 years ago
Read 2 more answers
PLEAS HELP ME
GarryVolchara [31]

\bf \qquad \qquad \textit{direct proportional variation} \\\\ \textit{\underline{y} varies directly with \underline{x}}\qquad \qquad y=kx\impliedby \begin{array}{llll} k=constant\ of\\ \qquad variation \end{array} \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ \stackrel{Table~A}{\begin{array}{ccll} x&y\\ \cline{1-2} 60&48\\70&56\\80&64 \end{array}}~\hspace{7em} \stackrel{Table~B}{\begin{array}{ccll} x&y\\ \cline{1-2} 20&24\\30&36\\40&48 \end{array}} \\\\[-0.35em] ~\dotfill


\bf \textit{for table A, we know that } \begin{cases} x=60\\ y=48 \end{cases}\implies 48=k60\implies \cfrac{48}{60}=k \\\\\\ \cfrac{4}{5}=k\qquad therefore\qquad \boxed{y=\cfrac{4}{5}x} \\\\\\ \textit{for table B, we know that } \begin{cases} x=30\\ y=36 \end{cases}\implies 36=k30\implies \cfrac{36}{30}=k \\\\\\ \cfrac{6}{5}=k\qquad therefore\qquad \boxed{y=\cfrac{6}{5}x}

4 0
3 years ago
What is the slope of (0,4) and (3,10)? Please helppppp a girl outt !
dem82 [27]

Answer:

M=6 OR slope=6

Step-by-step explanation:

Use slope formula

3 0
3 years ago
Read 2 more answers
Answer the question to become the brainliest
olya-2409 [2.1K]

Answer:

a) The distance travelled on the cycle in the first 14 seconds is 96 meters.

b) The acceleration in the first 4 seconds is 2 meters per square second.

Step-by-step explanation:

a) The distance travelled by the cycle is equal to the area below the curve, which is the sum of the first triangle and the rectangle:

\Delta x = \frac{1}{2}\cdot \left(8\,\frac{m}{s} \right) \cdot (4\,s-0\,s)+\left(8\,\frac{m}{s}\right)\cdot (14\,s-4\,s)

\Delta x = 16\,m +80\,m

\Delta x = 96\,m

The distance travelled on the cycle in the first 14 seconds is 96 meters.

b) The acceleration is represented by the slope of the line, which is determined by definition of secant line:

a = \frac{v(4\,s)-v(0\,s)}{4\,s-0\,s} (1)

a = \frac{8\,\frac{m}{s}-0\,\frac{m}{s}}{4\,s-0\,s}

a =2\,\frac{m}{s^{2}}

The acceleration in the first 4 seconds is 2 meters per square second.

7 0
3 years ago
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