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daser333 [38]
3 years ago
10

PLEASE, SOMEONE, I CAN'T FAIL THIS CLASS

Mathematics
1 answer:
Alenkasestr [34]3 years ago
8 0

\text{You're finding the applicable expression}\\\\\text{One way we could solve this is by plugging in the values in the left}\\\text{column to the expressions}\\\\\text{Lets plug in 2 to the first expression:}\\\\2^2+2+3\\\\\text{Solve:}\\\\4+2+3\\\\6+3=9\\\\\text{You would see that it gave you the right value, lets try it on another one:}\\\\3^2+3+3\\\\9+3+3\\\\12+3=15\\\\\text{This expression works}\\\\\boxed{x^2+x+3}

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Please explain how to solve this (<img src="https://tex.z-dn.net/?f=%20%5Csqrt%5B4%5D%7Ba%5E5%20b%5E3%7D%20" id="TexFormula1" ti
olchik [2.2K]
2 is the base and (\sqrt[4][a^5 b^3]) is the exponent.

the 4 is called an index and it means to fi d the fourth root of the expression under the (\sqrt[][text]) symbol.\\a fourth root is a factor that was multiplied four times. ex: 2*2*2*2=16. the fourth root of 16 is two. \\when you do square roots, you take the number representing the factor out of the radical. anything else that is not a square root stays under. ex: \\([tex]\sqrt[9][text])\\([tex]\sqrt[3*3*3][text]) there is one set of two 3's so\\([tex]3\sqrt[3][text])\\with a fourth root, you look for groups of four. the symbol of that group is placed outside the radical. anything else stays in.\\ ([tex]\sqrt[4][a^5 b^3])

(\sqrt[4][a*a*a*a*a*b*b*b]) there is one group of 4 a's so

(a\sqrt[4][a* b^3])

there really isn't anything else to do to simplify the expression
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