Answer:
Step-by-step explanation:
we know that the are of the square =a^2, where a is the side
64=a^2, sqrt of 64=8
all side are equal with 8
if you notice the triangle on the left-hand-side, it has a base of 8 ft and a height/altitude of 10.
now, the triangular pyramid has 3 of those triangles standing up, and one at the base lying down, so 4 triangles with that base and altitude. So we can simply find the area of all 4 of those triangles, sum them up and that's the area of the triangular pyramid.
![\bf \stackrel{\textit{area of the four triangles}}{4\left[ \cfrac{1}{2}(8)(10) \right]}](https://tex.z-dn.net/?f=%20%5Cbf%20%5Cstackrel%7B%5Ctextit%7Barea%20of%20the%20four%20triangles%7D%7D%7B4%5Cleft%5B%20%5Ccfrac%7B1%7D%7B2%7D%288%29%2810%29%20%5Cright%5D%7D%20)
Answer:
Step-by-step explanation:
Given that,
Rate of change of a function
1. From x = 1 to x = 4
2. From x = 5 to x =8
Then,
Rate of change for first condition
∆x/∆t = (x2-x1) / (t2-t1)
∆x/∆t = (4-1) / (t2-t1)
∆x/∆t = 3 / (t2-t1)
Rate of change for second condition
∆x/∆t = (x2-x1) / (t2-t1)
∆x/∆t = (8-5) / (t2-t1)
∆x/∆t = 3 / (t2-t1)
The rate of change are equal, it shows that the slope are equal.
So, it is a straight line function.
Since it has equal rate of change..
90 + 8 ? What are you asking? :)
NLM bc the angled correspond, making the triangles congruent
