Answer:
b
Step-by-step explanation:
If a = first term and r = common ratio we have
a + ar + ar^2 = 13 and ar^2 / a = r^2 = 9
so r = 3
and a + 3a + 9a = 13
so a = 1
so they are 1,3 and 9
2.
in geometric series we have
4 , 4r ,4r^2 , 60
Arithmetic;
4, 4r , 4r + d , 4r + 2d
so we have the system of equations
4r + 2d = 60
4r^2 = 4r + d
From first equation
2r + d = 30
so d = 30 - 2r
Substitute for d in second equation:-
4r^2 - 4r - (30-2r) = 0
4r^2 - 2r - 30 =0
2r^2 - r - 15 = 0
(r - 3)(2r + 5) = 0
r = 3 or -2.5
r must be positive so its = 3
and d = 30 - 2(3) = 24
and the numbers are 4*3 = 12 , 4*3^2 = 36
first 3 are 4 , 12 and 36 ( in geometric)
and last 3 are 12, 36 and 60 ( in arithmetic)
The 2 numbers we ause are 12 and 36.
Hi there!
To solve, we must use the following trig identity:
sin(u - v) = sin(u)cos(v) - sin(v)cos(u)
We can rewrite the left hand side of the equation as:

Split the fraction:

First fraction reduces to 1:

Simpify each with common arguments:

Answer:
10=19-11
Step-by-step explanation:
that answer is false because 19-11 = 8 not 10
Answer:
Step-by-step explanation:
1. Area of a parallelogram = base * height
area = 10 * 4 = 40 in squared
perimeter = 2(a + b)
perimeter = 2 * (5 + 10) = 2 * 15 = 30in
2. Area of triangle = 1/2 * base * height
area = 1/2 * 21 * 8 = 84 cm squared
perimeter = sum of outer perimeters
perimeter= 10cm + 17cm + 21cm = 48cm
3. area of trapezium = 1/2 * (a+b) * h
area = 1/2 * (6+12) * 4 = 36ft squared
perimeter = sum of outer perimeters
perimeter = 5ft + 6ft + 12ft + 5ft = 28ft