Honestly photo math works for everything
8x²+3y²=24
8x²+3y²-24=0
Let x be 1 ,
Therefore
8+3y²-24=0
3y²-16=0
3y²=16
y²=16/3
y=4/1.7
y=40/17
<em><u>Take</u></em><em><u> </u></em><em><u>different</u></em><em><u> </u></em><em><u>values</u></em><em><u> </u></em><em><u>of</u></em><em><u> </u></em><em><u>x</u></em><em><u> </u></em><em><u>&</u></em><em><u>y</u></em><em><u> </u></em><em><u>and</u></em><em><u> </u></em><em><u>plot</u></em><em><u> </u></em><em><u>a</u></em><em><u> </u></em><em><u>graph</u></em><em><u>!</u></em><em><u>!</u></em><em><u>!</u></em>
A. C(13, 10) = 13! = 13·12·11 = 13 · 2 · 11 = 286.C(13, 10) = 13! = 13·12·11 = 13 · 2 · 11 = 286.
B. P(13,10)= 13! =13! =13·12·11·10·9·8·7·6·5·4.
(13−10)! 3!
C. f there is exactly one woman chosen, this is possible in C(10, 9)C(3, 1) =
10! 3!
9!1! 1!2!
10! 3!
8!2! 2!1!
10! 3!
7!3! 3!0!
= 10 · 3 = 30 ways; two women chosen — in C(10,8)C(3,2) =
= 45·3 = 135 ways; three women chosen — in C(10, 7)C(3, 3) =
= 10·9·8 ·1 = 120 ways. Altogether there are 30+135+120 = 285
1·2·3
<span>possible choices.</span><span>
</span>
Answer:


Step-by-step explanation:
Given


Required
Determine the solution
Make x the subject of formula in: 

Divide both sides by 4


Substitute
in 

Solve the fraction

Open the bracket


Subtract 0.1 from both sides


Divide both sides by 0.2

Substitute 0 for y in 




Answer:
7 1/8 miles.
Step-by-step explanation: