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ollegr [7]
3 years ago
13

A ship sails 20 km west then 35 km south. Calculate how far it

Mathematics
2 answers:
amid [387]3 years ago
4 0

Answer:

40.3

Step-by-step explanation:

Use pythagoras theorem, a^2 + b^2 = c^2

400 + 1225 = 1625

sqrt of 1625 = approx 40.3

anzhelika [568]3 years ago
4 0

<em>Answer:</em>

<em>40, 3 km </em>

<em>Step-by-step explanation:</em>

<em>Pitagora </em>

<em>AC = √(AB² + BC²)</em>

<em>AC = √(20² + 35²)</em>

<em>AC = √(400 + 1225)</em>

<em>AC = √1625</em>

<em>AC ≈ 40,3 km </em>

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Step-by-step explanation:

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One container is filled with mixture that is 25% acid. A second container is filled with a mixture that is 55% acid. The second
algol13

Answer:

Therefore the third container contains   \frac{735}{17}\% = 43.23 %  acid.

Step-by-step explanation:

Given that, One container is filled with the mixture that 25% acid. 55% acid is contain by second container.

Let the volume of first container be x cubic unit.

Since the volume of second container is 55% larger than the first.

Then the volume of the second container is

= (V\times \frac{100+55}{100})   cubic unit.

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The amount of acid in first container is

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=\frac{25}{100}V  cubic unit.

The amount of acid in second container is

=(\frac{155}{100}V \times \frac{55}{100}) cubic unit.

=\frac{8525}{10000}V cubic unit.

Total amount of acid =(\frac{25}{100}V+\frac{8525}{10000}V) cubic unit.

                                   =(\frac{2500+8525}{10000}V) cubic unit.

                                   =(\frac{11025}{10000}V)cubic unit.

Total volume of mixture =(V+\frac{155}{100}V) cubic unit.

                                       =\frac{100+155}{100}V cubic unit.

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The amount of acid in the mixture is

=\frac{\textrm{The volume of acid}}{\textrm{The amount of mixture}}\times 100 \%

=\frac {\frac{11025}{10000}V}{\frac{255}{100}V}\times 100\%

=\frac{735}{17}\%

Therefore the third container contains  \frac{735}{17}\%  acid.

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