In triangle RST,angle R is a right angle .If TR = 6 and TS =8 what is the length of RS

Help! Will<br> Give that crown

wolverine [178]

Answer:

3500-26= <u>3474 </u>

3929-37=<u>3892</u>

any more help just ask :)

4 0

3 years ago

Two random samples were taken to determine how often people in a community listen to the local radio station each month.

tangare [24]

I do not get what the Question that you are asking is.

4 0

2 years ago

Brainliest to correct answer, hurry please!

omeli [17]

company A :

30,000 + 0.03(37499) = 31124.97...sales less then 37500

30,000 + 0.03(37501) = 31125.03....sales exceed 37500

30,000 + 0.03(249000) = 37470 ...sales less then 250000

30,000 + 0.03(251000) = 37530....sales exceed 250000

company B :

25,000 + 0.05(37499) = 26874.95...sales less then 37500

25,000 + 0.05(37501) = 26875.05...sales exceed 37500

25000 + 0.05(249000) = 37450...sales less then 250000

25,000 + 0.05(251000) = 37550...sales exceed 250000

so i believe your answer is option b,

company A pays better when sales are less then 250,000, but company B pays better when sales exceed 250,000 <==

5 0

3 years ago

Guests had to choose their meals from beef, chicken or vegetarian.

faltersainse [42]

1/3+5/12=4/12+5/12=9/12=3/4 of guests choose meat
1-3/4=1/4 of guests are vegetarians
so
23 guests is 1/4 of all guests
23*4=92 all guests

6 0

3 years ago

An insurance company states that it settles 85% of all life insurance claims within 30 days. A consumer group asks the state ins

BlackZzzverrR [31]

Using the z-distribution, it is found that since the p-value of the test is less than 0.05, we reject the null hypothesis and find that there is enough evidence to conclude that the true proportion of all life insurance claims made to this company that are settled within 30 days is less than 85%.

<h3>What are the hypothesis tested?</h3>

At the null hypothesis, it is tested if there is not enough evidence that the proportion is below 85%, that is:

$H_0: p \geq 0.85$

At the alternative hypothesis, it is tested if there is enough evidence that the proportion is below 85%, that is:

$H_0: p < 0.85$

<h3>What is the test statistic?</h3>

The test statistic is given by:

$z = \frac{\overline{p} - p}{\sqrt{\frac{p(1-p)}{n}}}$

In which:

$\overline{p}$ is the sample proportion.

p is the proportion tested at the null hypothesis.

n is the sample size.

For this problem, the parameters are:

$p = 0.85, n = 250, \overline{p} = \frac{203}{250} = 0.812$

Hence the test statistic is:

$z = \frac{\overline{p} - p}{\sqrt{\frac{p(1-p)}{n}}}$

$z = \frac{0.812 - 0.85}{\sqrt{\frac{0.85(0.15)}{250}}}$

z = -1.68

<h3>What is the p-value and the conclusion</h3>

Using a z-distribution calculator, with a left-tailed test, as we are testing if the proportion is less than a value, and z = -1.68, the p-value is of 0.0465.

Since the p-value of the test is less than 0.05, we reject the null hypothesis and find that there is enough evidence to conclude that the true proportion of all life insurance claims made to this company that are settled within 30 days is less than 85%.

More can be learned about the z-distribution at brainly.com/question/16313918

#SPJ1

4 0

1 year ago