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horrorfan [7]
3 years ago
14

In triangle RST,angle R is a right angle .If TR = 6 and TS =8 what is the length of RS

Mathematics
1 answer:
mylen [45]3 years ago
3 0
The length of RS is 10 because it's a 3-4-5 right triangle
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URGENT PLEASE HELP, respond to c, d, e, and f please !!
sertanlavr [38]

Answer:

Step-by-step explanation:

c. (18.5-17)/.9= 1.66666666667= 1.6667

d. .7107

e. .2185

f.  0.675=(x-17)/.9 x= 17.6075

8 0
3 years ago
Pleeeeeeeeaaaseeeeee help meeeeeeee!!!!!!!!!
zaharov [31]

Answer:

Option D.

A =96\pi\ cm^2

Step-by-step explanation:

The area of the circular bases is:

A_c = 2\pi(a) ^ 2

Where

a=4\ cm is the radius of the circle

Then

A = 2\pi(4) ^ 2

A = 32\pi\ cm^2

The area of the rectangle is:

A_r=b * 2\pi r

Where

b=8\ cm

b is the width of the rectangle and 2\pi r is the length

Then the area of the rectangle is:

A_r=8 * 2\pi (4)

A_r=64\pi\ cm^2

Finally the total area is:

A = A_c + A_r\\\\A = 32\pi\ cm^2 + 64\pi\ cm^2\\\\

A =96\pi\ cm^2

7 0
4 years ago
Read 2 more answers
2z -5(z +2) = -8 - 2z<br><br> Please explain!! Thank you
Korolek [52]

Follow PEMDAS.

You would first do your distributive property which is, -5(z+2). You would multiply -5 to z and -5 to 2 which will give you -5z + -10.

so now you have 2z-5z+ -10= -8 - 2z. Now you must isolate the variable. So subtract -8 to -10 which will give you -18.

Now you have the equation 2z-5z-18=-2z

Now combine like terms. 2z-5z= -3z

Now you have the equation -3z-18=-2z

Now you must move the -3z to the other side of the equal sign by adding the opposite which is +3z to -2z which will give you +1z

Now you have -18= 1z

Now you divide. -18 divided by 1 is -18.

So your final answer will be -18=z

7 0
3 years ago
For the graph, what is a reasonable constraint so that the function is at least 300?
blsea [12.9K]

Answer:

C) 0 ≤ x ≤ 25

Step-by-step explanation:

We are supposed to find a reasonable constraint so that the function is at least 300 i.e. the value of x at which f(x) is greater or equal to 300

A)x ≥ 0

Refer the graph

At x = 0

f(x)=300

On increasing the value of x , f(x) increases but at x = 12 it starts decreasing

So, x ≥ 0 can also have f(x)<300

So, Option A is wrong

B)−5 ≤ x ≤ 30

At x = -5

f(x) = 100

So, Option B is wrong since we require f(x) is greater or equal to 300

c)0 ≤ x ≤ 25

At x = 0

f(x)=300

At x = 12 , it starts decreasing

At x = 25

f(x)=300

So, The value of f(x) is at least 300 when 0 ≤ x ≤ 25

D)All real numbers

At x = 30

f(x)=0

But we require f(x) greater or equal to 300

Hence Option C is true

8 0
3 years ago
N(x)=2x+7;(x)=17, what is the value of x so that the function has a given value
miskamm [114]
2(17)+7

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N(17)=41

Brainliest?
5 0
3 years ago
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