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Naya [18.7K]
4 years ago
13

A pattern can be represented by the equationH = 6n-1.

Mathematics
1 answer:
Sergeeva-Olga [200]4 years ago
8 0

Answer:

The answer is b. i, iii, and iv

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What’s the equation for the order pairs (1,-5) and (-2,5)
liq [111]

\bf (\stackrel{x_1}{1}~,~\stackrel{y_1}{-5})\qquad
(\stackrel{x_2}{-2}~,~\stackrel{y_2}{5})
\\\\\\
slope = m\implies
\cfrac{\stackrel{rise}{ y_2- y_1}}{\stackrel{run}{ x_2- x_1}}\implies \cfrac{5-(-5)}{-2-1}\implies \cfrac{5+5}{-2-1}\implies \cfrac{10}{-3}


\bf \begin{array}{|c|ll}
\cline{1-1}
\textit{point-slope form}\\
\cline{1-1}
\\
y-y_1=m(x-x_1)
\\\\
\cline{1-1}
\end{array}\implies y-(-5)=-\cfrac{10}{3}(x-1)\implies y+5=-\cfrac{10}{3}x+\cfrac{10}{3}
\\\\\\
y=-\cfrac{10}{3}x+\cfrac{10}{3}-5\implies y=-\cfrac{10}{3}x-\cfrac{5}{3}

6 0
3 years ago
Please help I’ll give brainiest!
Marizza181 [45]

Answer: h(3)= -4 h(-3)=-16

Step-by-step explanation:

Plug in 3 and -3 for x and solve

h(3)= 2(3)-10

h(-3)= 2(-3)-10

4 0
3 years ago
2n +5)=2<br> Help me please
Kobotan [32]

Answer:

-1.5

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
Use the figure to determine the intersection of planes EAB and EFG
vredina [299]

Answer:

Option (3). EF

Step-by-step explanation:

From the figure attached,

Plane defined by EAB can be represented by the face EABF of the square prism also.

Similarly, plane EFG can be represented by the face EFGH of the prism.

Now these sides EABF and EFGH are joining each other at the edge EF of the cuboid.

Therefore, intersection of the given planes is EF.

Option (3) will be the answer.

7 0
4 years ago
The longer leg of a right triangle is 4 more than the short leg. The hypotenuse is eight less than the sum of the 2 legs.
Crazy boy [7]

Answer:

SteLet a = short leg of the right triangle, b = the longer leg, and c = the hypotenuse.

The longer leg of a right triangle is 4inches longer than the shorter leg: b = a + 4

The hypotenuse is 8inches longer than the shorter leg:  c = a + 8

 

Use the Pythagorean Theorem:

 

a2 + b2 = c2

a2 + (a+4)2 = (a+8)2

a2 + a2 + 8a + 16 = a2 + 16a + 64

a2 - 8a - 48 = 0

 

Factors to:

 

(a-12)(a+4) = 0

a = 12, -4

 

Since we can't have a side of -4, a = 12

Shorter Leg = 12 inches

Longer Leg = 12 + 4 = 16 inches

Hypotenuse = 12 + 8 = 20 inches

6 0
3 years ago
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