Write a fraction with a decimal value between 1/2 and 3/4

Write cp and sp i bought a suit rs 5750.00 and sold it at rs 5890.00?

Levart [38]

CP = Rs 5750.00

SP = Rs. 5890.00

$\rm \blue{\: mark \: brainleist \: }$

3 0

3 years ago

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Which vectors represent the reflection of the vector <3, -7> across the x-axis? A. [3/7} B. [-3/7] C. <-3, 7> D. &lt

Alexandra [31]

Answer:

D) < 3, 7)>

Step-by-step explanation:

<u><em>Explanation</em></u>:-

Given that the vector < 3 , -7 >

Given the vector reflection across the x-axis

(x,y) → (x , -y)

The vector < 3,-7> →< 3, -(-7)>

< 3,-7> →< 3, 7)>

3 0

3 years ago

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Please help me find the area of shaded region and step by step

Bumek [7]

Answer:

Part 1) $A=60\ ft^2$

Part 2) $A=80\ cm^2$

Part 3) $A=96\ m^2$

Part 4) $A=144\ cm^2$

Part 5) $A=9\ m^2$

Part 6) $A=(49\pi -33)\ in^2$

Step-by-step explanation:

Part 1) we know that

The shaded region is equal to the area of the complete rectangle minus the area of the interior rectangle

The area of rectangle is equal to

$A=bh$

where

b is the base of rectangle

h is the height of rectangle

so

$A=(12)(7)-(8)(3)$

$A=84-24$

$A=60\ ft^2$

Part 2) we know that

The shaded region is equal to the area of the complete rectangle minus the area of the interior square

The area of square is equal to

$A=b^2$

where

b is the length side of the square

so

$A=(12)(8)-(4^2)$

$A=96-16$

$A=80\ cm^2$

Part 3) we know that

The area of the shaded region is equal to the area of four rectangles plus the area of one square

so

$A=4(4)(5)+(4^2)$

$A=80+16$

$A=96\ m^2$

Part 4) we know that

The shaded region is equal to the area of the complete square minus the area of the interior square

so

$A=(15^2)-(9^2)$

$A=225-81$

$A=144\ cm^2$

Part 5) we know that

The area of the shaded region is equal to the area of triangle minus the area of rectangle

The area of triangle is equal to

$A=\frac{1}{2}(b)(h)$

where

b is the base of triangle

h is the height of triangle

so

$A=\frac{1}{2}(6)(7)-(6)(2)$

$A=21-12$

$A=9\ m^2$

Part 6) we know that

The area of the shaded region is equal to the area of the circle minus the area of rectangle

The area of the circle is equal to

$A=\pi r^{2}$

where

r is the radius of the circle

so

$A=\pi (7^2)-(3)(11)$

$A=(49\pi -33)\ in^2$

7 0

3 years ago

Which equation shows how to find the place value relationship between the first 6 and the second 6 in 662? 60 ÷ 6 = 10 600 – 60

natita [175]

Answer:

600÷60=10

Step-by-step explanation:

six hundred is ten times sixty

6 0

3 years ago

The numbers 81, 45,27 are multiplies of

malfutka [58]

They are multiplis of 9

4 0

3 years ago

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