2 years ago

find the point on the terminal side of θ = negative three pi divided by four that has an x coordinate of negative 1

1 answer:

4 0

Check the picture below, is a negative angle, thus, is going "clockwise"

$\bf tan(\theta)=\cfrac{opposite}{adjacent}\qquad tan\left( -\frac{3\pi }{4} \right)=\cfrac{y}{x}\implies tan\left( -\frac{3\pi }{4} \right)=\cfrac{y}{-1}
\\\\\\
-1\cdot tan\left( -\frac{3\pi }{4} \right)=y\implies -1\cdot \cfrac{sin\left( -\frac{3\pi }{4} \right)}{cos\left( -\frac{3\pi }{4} \right)}=y
\\\\\\
-1\cdot \cfrac{-1}{-1}=y\implies -1$

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