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givi [52]
4 years ago
7

Find the missing angle

Mathematics
2 answers:
xxMikexx [17]4 years ago
6 0

Answer:

D 40 go down have a nice day

Step-by-step explanation:

den301095 [7]4 years ago
6 0
D = 40

The angles of a triangle add up to 180 degrees. So 80 + 60 + 40 = 180
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(4x+___)+(2x+3)=6x+5<br> Find the missing term.
SOVA2 [1]

Answer:

(4x+2)+(2x+3)=6x+5

Step-by-step explanation:

(4x+___)+(2x+3)=6x+5

4x+2x=6x

5-3=?

5-3=2

2

7 0
3 years ago
GIVING BRAINLIEST
Umnica [9.8K]

Answer:

140

Step-by-step explanation:

180 - 40 = 140

7 0
2 years ago
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Describe how the graph of y=log (10 000x) is related to the graph of y=log x
Nana76 [90]
Background: log (a . b) = log a + log b 
hence log(10000x) = log 10000 + log x but we know that log 10000 = 4
                               = 4 + log x 
therefore the graph of log(10000x) is just the graph of log x transposed by 4 
5 0
3 years ago
Aria drank 500 milliliters of water after her run. Her best friend, Andrea, drank 0.75 liter of water. Who drank more?
Paul [167]
To answer this item, let us convert first one of the given dimension such that both numbers will take only the same units for easier comparison. It should be noted that every liter (L) is consists of 1000 mL. 

Aria: (500 mL)(1 L/1000 mL) = 0.5 L
Andrea: 0.75 L

Since, 0.75 L is higher compared to 0.5L, the answer to the item is Andrea. 
8 0
3 years ago
Given: △ACM, m∠C=90°, CP ⊥ AM
larisa86 [58]

Answer:  The answer is 3\dfrac{4}{7}.

Step-by-step explanation:  Given in the question that ΔAM is a right-angled triangle, where ∠C = 90°, CP ⊥ AM, AC : CM = 3 : 4 and MP - AP = 1. We are to find AM.

Let, AC = 3x and CM = 4x.

In the right-angled triangle ACM, we have

AM^2=AC^2+CM^2=(3x)^2+(4x)^2=9x^2+16x^2=25x^2\\\\\Rightarrow AM=5x.

Now,

AM=AP+PM=AP+(AP+1)\\\\\Rightarrow 2AP=AM-1\\\\\Rightarrow 2AP=5x-1.~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~(A)

Now, since CP ⊥ AM, so ΔACP and ΔMCP are both right-angled triangles.

So,

CP^2=AC^2-AP^2=CM^2-MP^2\\\\\Rightarrow (3x)^2-AP^2=(4x)^2-(AP+1)^2\\\\\Rightarrow 9x^2-AP^2=16x^2-AP^2-2AP-1\\\\\Rightarrow 2AP=7x^2-1.~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~(B)

Comparing equations (A) and (B), we have

5x-1=7x^2-1\\\\\Rightarrow 5x=7x^2\\\\\Rightarrow x=\dfrac{5}{7},~\textup{since }x\neq 0.

Thus,

AM=5\times\dfrac{5}{7}=\dfrac{25}{7}=3\dfrac{4}{7}.

8 0
4 years ago
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