Answer:
0.1505 = 15.05% probability that the hockey team wins 6 games in November
Step-by-step explanation:
For each game, there are only two possible outcomes. Either the team wins, or it does not. The probability of winning a game is independent of winning other games. So we use the binomial probability distribution to solve this question.
Binomial probability distribution
The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

In which
is the number of different combinations of x objects from a set of n elements, given by the following formula.

And p is the probability of X happening.
The probability that a certain hockey team will win any given game is 0.3723
So 
12 games in November
So 
What is the probability that the hockey team wins 6 games in November?
This is 


0.1505 = 15.05% probability that the hockey team wins 6 games in November
Answer:
D
Step-by-step explanation:
f(x) = -3x^3 + x^2 – 3 f(2) means that wherever you see a x, put in a 2.
f(2)= -3(2)^3 + (2)^2 - 3
f(2) = -3*8 + 4 - 3
f(2) = - 24 + 1
f(2) = - 23
Answer:
y = 7 and x =3
Step-by-step explanation:
use elimination method
so we gonna eliminate y first
9x = 1 - 4y
-7x = -7 + 4y
7| 9x = 1 - 4y
9| -7x = -7 + 4y
63x = 7 - 28y
-63x = -63 + 36y
add eqtn 1 to eqtn2
you will get
0 = -56 + 8y
56 = -56 + 56 + 8y
56 = 8y
56÷8 = 8y÷ 8
7 = y
also eliminate x as we have done wth y
4| 9x = 1 - 4y
4| -7x = -7 + 4y
36x = 4 - 16y
-28x = -28 + 16y
add the two equations
u will get
8x = -24 + 0
8x = -24
8x÷8 = 24÷ 8
x = 3
Answer:
<em>The voltage at the middle source is</em> 
Step-by-step explanation:
<u>Voltage Sources in Series</u>
When two or more voltage sources are connected in series, the total voltage is the sum of the individual voltages of each source.
The figure shown has three voltage sources of values:



The sum of these voltages is:

Operating:

We know the total voltage is
, thus:

Equating the real parts and the imaginary parts independently:
4+a=6
1+b=-3
Solving each equation:
a = 2
b = -4
The voltage at the middle source is 