How many edges are in a quadrilateral prism

While in Europe, if you drive 123 km per day, how much money would you spend on gas in one week if gas costs 1.10 euros per lite

Leona [35]

First, you drive 123km per day, and they ask for in a week.
There are 7 days in a week, we have to multiply 123 by 7, which equals 861.
=km per week 861
Now, we need to find out how much cost the gas. Gas cost 1.10 euros per-liter, and this problem wants us to assume that 1euro = 1.26 dollars.

So, we divide 1.10 by 1.26 which is 0.87.
=gas cost 0.87 per liter.

Next, this person goes 31.0 mi/gal per stop.
To get the answer we need to divide 861 the full distance in a week and divide it by how many stops nee to be made which is each 31 mi/gal.

So, 861/31 = 27.77 and now we times 0.87 by 27.77 to get gas cost.
=24.16

6 0

4 years ago

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Two-times of the sum of 3 and y

notka56 [123]

2x3=y thats what i think not for shure

8 0

3 years ago

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Evaluate the expression 2(8 − 4)2 − 10 ÷ 2 please help

Stolb23 [73]

Answer:

11

Step-by-step explanation:

3 0

3 years ago

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The probability that a randomly selected teenager watched a rented video at least once during a week was 0.75. What is the proba

Whitepunk [10]

Answer:

There is a 75.65% probability that at least 5 teenagers in a group of 7 watched a rented movie at least once last week.

Step-by-step explanation:

For each teenager, there are only two possible outcomes. Either they watched a rented video at least once during a week, or they did not. This means that we can solve this problem using the binomial probability distribution.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinatios of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

In this problem we have that:

The probability that a randomly selected teenager watched a rented video at least once during a week was 0.75. This means that $p = 0.75$ .

What is the probability that at least 5 teenagers in a group of 7 watched a rented movie at least once last week?

Group of 7, so $n = 7$ .

$P(X \geq 5) = P(X = 5) + P(X = 6) + P(X = 7)$ .

In which

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 5) = C_{7,5}.(0.75)^{5}.(0.25)^{2} = 0.3115$

$P(X = 6) = C_{7,6}.(0.75)^{6}.(0.25)^{1} = 0.3115$

$P(X = 7) = C_{7,7}.(0.75)^{7}.(0.25)^{0} = 0.1335$

So

$P(X \geq 5) = P(X = 5) + P(X = 6) + P(X = 7) = 0.3115 + 0.3115 + 0.1335 = 0.7565$ .

There is a 75.65% probability that at least 5 teenagers in a group of 7 watched a rented movie at least once last week.

3 0

3 years ago

A grocery store display has 60 oranges and 18 apples. What is the ratio of oranges to apples?

Setler [38]

Hi! So, a ratio is basically comparing one amount to another. And you do that by putting the first number, a colon, and the second number.

So, it's asking for oranges to apples. There's 60 oranges, and 18 apples. So you write:

60:18

7 0

4 years ago

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