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rodikova [14]
3 years ago
13

Solve for a. 2/3a^2=30

Mathematics
1 answer:
malfutka [58]3 years ago
6 0

<u>Answer:</u>

a = \frac { \sqrt { 5 } } { 1 5 } ,\:a = -\frac {\sqrt{5}}{15}

<u>Step-by-step explanation:</u>

We are given the following expression which are to solve for a and give the answer in radical form:

\frac{2}{3a^2} =30

To solve this, we will multiply both the sides by 3a^2 to get:

\frac{2}{3a^2}\cdot \:3a^2=30\cdot \:3a^2

Simplify it to get:

2=90a^2

a = \frac { \sqrt { 5 } } { 1 5 } ,\:a = -\frac {\sqrt{5}}{15}

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3 years ago
Examine the linear table to find the slope, y-intercept, and write the equation for this linear relationship ​. NEED HELP PLEASE
gizmo_the_mogwai [7]

Answer:

y = \frac{4}{3} x + 17  

Step-by-step explanation:

The table shows a set of x and y values, thus showing a set of points we can use to find the equation.

1) First, find the slope by using two points and substituting their x and y values into the slope formula, \frac{y_2-y_1}{x_2-x_1}. I chose (-3, 13) and (0,17), but any two points from the table will work. Use them for the formula like so:

\frac{(17)-(13)}{(0)-(-3)} \\= \frac{17-13}{0+3} \\= \frac{4}{3}

Thus, the slope is \frac{4}{3}.

2) Next, identify the y-intercept. The y-intercept is where the line hits the y-axis. All points on the y-axis have a x value of 0. Thus, (0,17) must be the y-intercept of the line.

3) Finally, write an equation in slope-intercept form, or y = mx + b format. Substitute the m and b for real values.

The m represents the slope of the equation, so substitute it for \frac{4}{3}. The b represents the y-value of the y-intercept, so substitute it for 17. This will give the following answer and equation:

y = \frac{4}{3} x + 17

7 0
3 years ago
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