3 years ago

Find the equation, in standard form, of the line passing through the points (3,-4) and (5,1)

1 answer:

7 0

$m = \frac{y_{2} - y_{1}}{x_{2} - x_{1}} = \frac{1 - (-4)}{5 - 3} = \frac{1 + 4}{2} = \frac{5}{2} = 2\frac{1}{2} \\\\y - y_{1} = m(x - x_{1}) \\y - (-4) = 2\frac{1}{2}(x - 3) \\y + 4 = 2\frac{1}{2}(x) - 2\frac{1}{2}(3) \\y + 4 = 2\frac{1}{2}x - 7\frac{1}{2} \\y = 2\frac{1}{2}x - 11\frac{1}{2}$

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