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vladimir2022 [97]
3 years ago
15

In the accompanying diagram of parallelogram ABCD, LaTeX: m\angle A=x+17 m ∠ A = x + 17 and LaTeX: m\angle C=2x-4 m ∠ C = 2 x −

4 . Find the value of x.

Mathematics
1 answer:
jek_recluse [69]3 years ago
3 0
Answer:
x = 21

Explanation:
In a parallelogram, each two opposite angles are equal.

In the given parallelogram ABCD, we can note that angles A and C are opposite angles. This means that they have equal measures.

Therefore:
∠A = ∠C
x + 17 = 2x - 4
17 + 4 = 2x - x
x = 21

We can check:
angle A = 21 + 17 = 38°
angle C = 2(21) - 4 = 38°
They are equal

Hope this helps :)

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Answer:

x = 161/10 = 16.100

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The table displays the quantitative data, two teachers do not wear glasses, and a total of 6 teachers were polled. Then the correct option is A, C, and E.

<h3>What is decision-making?</h3>

The process of making choice is by identifying the correct decision, gathering information, and assessing alternative solutions.

The table is shown below.

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Student                  32                              97                       129

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4 0
2 years ago
A model rocket is launched straight upward. The solid fuel propellant pushes the rocket off the ground at an initial velocity of
anastassius [24]

Answer:

a) 72.25sec

b) 6.25secs

c) after 10.5secs and 2 secs

Step-by-step explanation:

Given the height reached by the rocket expressed as;

s(t)= -4t^2 + 50t - 84

At maximum height, the velocity of the rocket is zero i.e ds/dt  = 0

ds/dt = -8t + 50

0 = -8t + 50

8t = 50

t = 50/8

t = 6.25secs

Hence it will reach the maximum height after 6.25secs

To get the maximum height, you will substitute t - 6.25s into the given expression

s(t)= -4t^2 + 50t - 84

s(6.25) = -4(6.25)^2 + 50(6.25) - 84

s(6.25) = -156.25 + 312.5 - 84

s(6.25)  = 72.25feet

Hence the maximum height reached by the rocket is 72.25feet

The rocket will reach the ground when s(t) = 0

Substitute into the expression

s(t)= -4t^2 + 50t - 84

0 = -4t^2 + 50t - 84

4t^2 - 50t + 84 = 0

2t^2 - 25t + 42 = 0

2t^2 - 4t - 21t + 42 = 0

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(2t - 21) (t - 2) = 0

2t - 21 = 0 and t - 2 = 0

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t = 10.5 and 2

Hence the time the rocket will reach the ground are after 10.5secs and 2 secs

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Ahat [919]

Answer:

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Answer:

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Step-by-step explanation:

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