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madreJ [45]
3 years ago
13

A new car is available with standard or automatic transmission, two or four doors, and it is available in 10 exterior colors. Wh

at is the number of possible outcomes? a.14 b.40 c.44 d.104
Mathematics
1 answer:
dezoksy [38]3 years ago
3 0

Answer:

<em>40</em>

Step-by-step explanation:

Given that:

Number of options available for transmission = 2 (Standard or Automatic)

Number of options for doors = 2 (2 doors or 4 doors)

Number of exterior colors available = 10

To find:

Total number of outcomes = ?

Solution:

First of all, let us calculate the number of outcomes for the transmission mode and number of doors options.

1. Standard - 2 doors

2. Standard - 4 doors

3. Automatic - 2 doors

4. Automatic - 4 doors

Number of outcomes possible = 4 (which is equal to number of transmission mode available multiplied by number of doors options i.e. 2\times 2)

Now, these 4 will be mapped with 10 different exterior colors.

Therefore total number of outcomes possible :

Number of transmission modes \times Number of doors options  \times Number of exterior colors

2 \times 2 \times 10 = <em>40</em>

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Answer:

\frac{7}{4} local calls per 1 long distance call.

Step-by-step explanation:

Local calls =35

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3 years ago
Can someone help me find the equivalent expressions to the picture below? I’m having trouble
miss Akunina [59]

Answer:

Options (1), (2), (3) and (7)

Step-by-step explanation:

Given expression is \frac{\sqrt[3]{8^{\frac{1}{3}}\times 3} }{3\times2^{\frac{1}{9}}}.

Now we will solve this expression with the help of law of exponents.

\frac{\sqrt[3]{8^{\frac{1}{3}}\times 3} }{3\times2^{\frac{1}{9}}}=\frac{\sqrt[3]{(2^3)^{\frac{1}{3}}\times 3} }{3\times2^{\frac{1}{9}}}

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           =\frac{2^{\frac{1}{3}}\times 3^{\frac{1}{3}}}{3\times 2^{\frac{1}{9}}}

           =2^{\frac{1}{3}}\times 3^{\frac{1}{3}}\times 2^{-\frac{1}{9}}\times 3^{-1}

           =2^{\frac{1}{3}-\frac{1}{9}}\times 3^{\frac{1}{3}-1}

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           =2^{\frac{2}{9}}\times 3^{-\frac{2}{3} } [Option 2]

2^{\frac{2}{9}}\times 3^{-\frac{2}{3} }=(\sqrt[9]{2})^2\times (\sqrt[3]{\frac{1}{3} } )^2 [Option 1]

2^{\frac{2}{9}}\times 3^{-\frac{2}{3} }=(\sqrt[9]{2})^2\times (\sqrt[3]{\frac{1}{3} } )^2

                =(2^2)^{\frac{1}{9}}\times (3^2)^{-\frac{1}{3} }

                =\sqrt[9]{4}\times \sqrt[3]{\frac{1}{9} } [Option 3]

2^{\frac{2}{9}}\times 3^{-\frac{2}{3} }=(2^2)^{\frac{1}{9}}\times (3^{-2})^{\frac{1}{3} }

               =\sqrt[9]{2^2}\times \sqrt[3]{3^{-2}} [Option 7]

Therefore, Options (1), (2), (3) and (7) are the correct options.

6 0
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