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prohojiy [21]
3 years ago
8

5y+4-2y=9How can I solve this equation​

Mathematics
1 answer:
Gennadij [26K]3 years ago
3 0

Answer:

y = 5/3 = 1.667

Step-by-step explanation:

Simplifying

5y + 4 + -2y = 9

Reorder

4 + 5y + -2y = 9

Solving

4 + 3y = 9

Solving for y:

Add -4 to each side of the equation.

4 + -4 + 3y = 9 + -4

Combine like terms.

4 + -4 = 0

0 + 3y = 9 + -4

3y = 9 + -4

Combine like terms.

9 + -4 = 5

3y = 5

Divide each side by 3

y = 1.666666667

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\frac{4}{2}  =  \frac{9}{x}  \\

perform cross multiplication:

(4 \times x) = 9 \times 2 \\ 4x = 18 \\ → \: { \tt{x = 4.5}}

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\huge\boxed{(3^4)^4=3^8\cdot3^8}\\\boxed{4^3\cdot5^3=20^3}\\\boxed{(4^3)^3=4^3\cdot4^3\cdo4^3}

Step-by-step explanation:

a^n\cdot a^n=a^{n+m}\\\\(a^n)^m=a^{n\cdot m}\\\\(a\cdot b)^n=a^n\cdot b^n\\=====================

(4^3)^3=4^{3\cdot3}=4^9\\4^3\cdot4^3=4^{3+3}=4^6\\\\4^9\neq4^6\to(4^3)^3\neq4^3\cdot4^3\\==================

(3^4)^4=3^{4\cdot4}=3^{16}\\3^8\cdot3^8=3^{8+8}=3^{16}\\\\(3^4)^4=3^8\cdot3^8\\================

6^4\cdot3^4=(6\cdot3)^4=18^4\\\\18^4\neq18^8\to6^4\cdot3^4\neq18^8\\=================

4^3\cdot5^3=(4\cdot5)^3=20^3\\\\4^3\cdot5^3=20^3\\=================

(4^3)^3=4^{3\cdot3}=4^9\\4^3\cdot4^3\cdot4^3=4^{3+3+3}=4^9\\\\(4^3)^3=4^3\cdot4^3\cdot4^3

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