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3 years ago

Match each step to its justification to solve 2x+5=19

Mathematics

2 answers:

loris [4]3 years ago

6 0

The steps :

given
subtraction property of equality
subtract
division property of equality
divide

<h3>Further Explanation </h3>

One variable linear equation is an equation that has a variable and the exponent number is one. Can be stated in the form:

$\large{\boxed{\bold{ax=b}}}$

ax + b = c, where a, b, and c are constants, x is a variable

Whereas the two-variable linear equation is a linear equation that has 2 variables and the exponent is one

Can be stated in the form:

$\large{\boxed{\bold{ax+by=c}}}$

ax + by = c

x, y = variable

There are 2 general steps to solving a linear equation of one variable:

1. add or subtract both segments with the same number so that it is expected that in one segment there are only variable modifiers or constant numbers

2. Change the equation into a simple form so that the coefficient of the variable is 1

This can be done by dividing or multiplying by equal numbers

An equation will remain equivalent if both segments are multiplied or divided by the same number

In the equation

2x + 5 = 19

The right steps to complete it according to the images included are:

1. 2x + 5 = 9 ⇒ given

2. both segments are subtracted by the number 5

2x + 5 -5 = 9-5 ⇒subtraction property of equality

3. 2x = 14 ⇒subtract

4. both segments are divided by 2 so that the coefficient x = 1

${\frac {2x} {2}}=~\frac{14}{2$

⇒division property of equality

5. x = 7 ⇒ divide

<h3>Learn more </h3>

the slope-intercept form of the linear equation

brainly.com/question/1945934

a graph of a linear equation

brainly.com/question/1505806

system of linear equations

brainly.com/question/11544167

Keywords: variable, linear equation

Nataliya [291]3 years ago

5 0

It is the steps to get to that certain step
some of the steps are out of order
I'm going to assign letters

the order is
A: 2x+5=19
B: 2x+5-5=19-5
C: 2x=14
D: 2x/2=14/2
E: x=7

A: given
B: we subtracted 5 from both sides so subtraction property of equality
C: subtract
D: divison property of equality (we divide both side by 2)
E: divide

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(a)

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Again consider,

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Now find $\frac{dB}{dA}$

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$\cos {B}.\frac{dB}{dA}=\sqrt{\frac{3}{2}}\cos A\\\\\frac{dB}{dA}=\sqrt{\frac{3}{2}}.\frac{\cos A}{\cos B}$

When $A=\frac{\pi}{4},B=\frac{\pi}{3}$ , the value of $\frac{dB}{dA}$ is,

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In general, the linear approximation at x= a is,

$f(x)=f'(x).(x-a)+f(a)$

Here the function $f(A)=B=\sin^{-1}[\sqrt{\frac{3}{2}}\sin{A}]$

At $A=\frac{\pi}{4}$

$f(\frac{\pi}{4})=B=\sin^{-1}[\sqrt{\frac{3}{2}}\sin{\frac{\pi}{4}}]\\\\=\sin^{-1}[\sqrt{\frac{3}{2}}.\frac{1}{\sqrt{2}}]\\\\\=\sin^{-1}(\frac{\sqrt{2}}{2})\\\\=\frac{\pi}{3}$