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2 years ago

How to find domain and range of a parabola?

1 answer:

german2 years ago

8 0

The domain is the value of x, the range is the value of y.
A parabola opens infinitely to the right and left, so x can be any number, the domain is all real numbers
Vertically, however, a parabola opens only one way, either upward or downward. when it opens upward from a a certain level, say, the lower point (the vertex) has a y coordinate of 2, we say the range is all real numbers larger than or equal to 2, or y≥2. When it opens downward, we say the range is all real numbers smaller or equal to 2, y≤2

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F(x)=x+3 , G(x)=x^2-2<br> (F/G)(-1)-G(3)

trapecia [35]

$f(x)=x+3;\ g(x)=x^2-2\\\\\left(\dfrac{f}{g}\right)(-1)-g(3)=?\\\\\left(\dfrac{f}{g}\right)(x)=\dfrac{f(x)}{g(x)}\\\\g(3)=3^2-2=9-2=7\\\\f(-1)=-1+3=2\\\\g(-1)=(-1)^2-2=1-2=-1\\\\\left(\dfrac{f}{g}\right)(-1)-g(3)=\dfrac{2}{-1}-7=-2-7=-9$

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2 years ago

I have no idea what to do with this someone help

joja [24]

The given distance of 5.20 would be A.

Replace A with 5.20 to solve for T.

T = 5.20^3/2
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4 0

2 years ago

Read 2 more answers

Which property of multiplication is used in the multiplication below?

olasank [31]

Zero property because you are using zeros to multiply

4 0

2 years ago

How many solutions does the system have?<br> 3x + y = 8<br> 2 + 2y = 8

REY [17]

Answer:

x=2,y=2

Step-by-step explanation:

This question is a simultaneous equation

So let's solve

3x+y=8...(1)

2x+2y=8....(2)

Multiply (1) by 2

6x+2y=16...(3)

Substrate (2) From (3)

4x=8

Let's make x the subject of formula by dividing both sides by 4

x=2

So let's substitute the value of x into (1)

3x+y=8

3(2)+y=8

6+y=8

y=8-6

y=2

Therefore x is 2,y is 2

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3 years ago

Find each product<br> (n-6)(n+6)

Brilliant_brown [7]

Answer:

n squared - 10n + 24

Step-by-step explanation:

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3 years ago