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Ksenya-84 [330]
3 years ago
13

How to find domain and range of a parabola?

Mathematics
1 answer:
german3 years ago
8 0
The domain is the value of x, the range is the value of y.
A parabola opens infinitely to the right and left, so x can be any number, the domain is all real numbers
Vertically, however, a parabola opens only one way, either upward or downward. when it opens upward from a a certain level, say, the lower point (the vertex) has a y coordinate of 2, we say the range is all real numbers larger than or equal to 2, or y≥2. When it opens downward, we say the range is all real numbers smaller or equal to 2, y≤2
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If the figure below are similar with a scale factor of 2:3, find the value of x.
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Step-by-step explanation:

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2 years ago
If f(x) = x² – 5, evaluate: f(x+h)-f(x)/<br> h
Likurg_2 [28]

The first derivative of the function f(x) = x² - 5 is equal to f'(x) = 2 · x.

<h3>How to find the derivative of a quadratic equation by definition of derivative</h3>

In this question we have a quadratic function, in which we must make use of the definition of derivative to find the expression of its first derivative. Then, the procedure is shown below:

f(x) = x² - 5                                         Given

f' = [(x + h)² - 5 - x² + 5] / h                Definition of derivative

(x² + 2 · x · h + h² - 5 - x² + 5) / h       Perfect square trinomial

(2 · x · h + h²) / h                                Associative, commutative and modulative properties / Existence of additive inverse

2 · x + h                                              Distributive, commutative and associative properties / Definition of division / Existence of multiplicative inverse

2 · x                                                     h = 0 / Result

The first derivative of the function f(x) = x² - 5 is equal to f'(x) = 2 · x.

To learn more on derivatives: brainly.com/question/25324584

#SPJ1

6 0
2 years ago
Solve for x in triangle
fenix001 [56]
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Hope this helps.
7 0
2 years ago
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