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Ksenya-84 [330]
3 years ago
13

How to find domain and range of a parabola?

Mathematics
1 answer:
german3 years ago
8 0
The domain is the value of x, the range is the value of y.
A parabola opens infinitely to the right and left, so x can be any number, the domain is all real numbers
Vertically, however, a parabola opens only one way, either upward or downward. when it opens upward from a a certain level, say, the lower point (the vertex) has a y coordinate of 2, we say the range is all real numbers larger than or equal to 2, or y≥2. When it opens downward, we say the range is all real numbers smaller or equal to 2, y≤2
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2. Carl needs 15 hours longer than Jennifer to paint a room. If they work together, they can complete the job in 4 hours. Explai
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Answer:

Jennifer would complete the job on her own in 5 hours.

Step-by-step explanation:

Solving a quadratic equation:

Given a second order polynomial expressed by the following equation:

ax^{2} + bx + c, a\neq0.

This polynomial has roots x_{1}, x_{2} such that ax^{2} + bx + c = a(x - x_{1})*(x - x_{2}), given by the following formulas:

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x_{2} = \frac{-b - \sqrt{\Delta}}{2*a}

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Rates

The together rate is the sum of their separates rate.

We have that:

Jennifer takes x hours to complete the job on her own, so her rate is 1/x.

Carl needs 15 hours longer than Jennifer, that is, 15 + x hours, so his rate is 1/(15+x).

The together rate is 1/4. So

\frac{1}{4} = \frac{1}{x} + \frac{1}{15+x}

\frac{1}{4} = \frac{15 + x + x}{x(15+x)}

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Applying cross multiplication.

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x_{1} = \frac{-7 + \sqrt{289}}{2} = 5

x_{2} = \frac{-7 - \sqrt{289}}{2} = -12

Since the time to complete the job has to be a positive value.

Jennifer would complete the job on her own in 5 hours.

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