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lesantik [10]
3 years ago
7

Anybody please help me with this.... I have a very important grade relying on this

Mathematics
2 answers:
Margaret [11]3 years ago
5 0
5. 11
...................................

Anon25 [30]3 years ago
3 0
Five is 11 and negative 11 because double negative equals a positive
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How do you do this math
Basile [38]

Answer: y = -3x - 6

Step-by-step explanation:

One way to write a <u>linear equation</u> is with slope-intercept form.               Slope-intercept form is y = mx + b, where m is the slope, and b is the              y-intercept.

Thus, the equation is y = -3x - 6

Hope it helps :) and let me know if you are confused anywhere.

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3a^2 *5a \to \boxed{15a^3}
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PLEASEEEEEEE HELP SOMEONE WHO DOESNT NO MATH
Anuta_ua [19.1K]
No this is not a function because 4 is used twice on the y side
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Step-by-step explanation:

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Pleaseeeeeee help mee
BlackZzzverrR [31]

Answer:

The solution of the given trigonometric equation

                   x = \frac{\pi }{6}

Step-by-step explanation:

<u><em>Step(i):</em></u>-

Given  

                cos( 3x - \frac{\pi }{3} )  = \frac{\sqrt{3} }{2}

                  cos( 3x - \frac{\pi }{3} )  = cos (\frac{\pi }{6} )

                      3x - \frac{\pi }{3}  =  \frac{\pi }{6}

                      3x - \frac{\pi }{3  } + \frac{\pi }{3}   =  \frac{\pi }{6} + \frac{\pi }{3}

                      3x = \frac{2\pi +\pi }{6} = \frac{3\pi }{6} = \frac{\pi }{2}

                     x = \frac{\pi }{6}

<u><em>Step(ii)</em></u>:-

The solution of the given trigonometric equation

                   x = \frac{\pi }{6}

<u><em>verification </em></u>:-

      cos( 3x - \frac{\pi }{3} )  = \frac{\sqrt{3} }{2}

put  x = \frac{\pi }{6}

    cos( 3(\frac{\pi }{6})  - \frac{\pi }{3} )  = \frac{\sqrt{3} }{2}

    cos (\frac{\pi }{6} ) = \frac{\sqrt{3} }{2} \\\\\frac{\sqrt{3} }{2} =  \frac{\sqrt{3} }{2}

Both are equal

∴The solution of the given trigonometric equation

                   x = \frac{\pi }{6}

                     

4 0
2 years ago
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