There's this app where you get a picture of the math problem and it gives you the answer
Option 3 is not possible
-60.2 + 32 = -60.2 + 60
And these are not equal
Rest all options have x and are solvable
Must click thanks and mark brainliest
Example: Does the point (5, 2) lie within the solution set of the given system of inequalities?
y ≤ x − 5
y ≥ −x − 4
Focus on the first inequality. Does (5,2) satisfy this inequality? Is 2 ≤ 5 - 0 true? Yes, it is true. Before we call (5,2) a solution, we must determine whether or not (5,2) also satisfies the 2nd inequality: Is 2 ≥ -(5) - 4 true?
Is 2 ≥ -9? Yes! So, yes, (5,2) is a solution of this system of inequalities.
We must check out the other three possible solutions in the same fashion.
Try out the point (5,-2). Does it satisfy both inequalities?
Focusing on the first inequality: Is -2 ≤ 5 - 5 true? Yes, it is. The key question here and now is whether or not (5,-2) also satisfies y ≥ −x − 4. Is
-2 ≥ -(5) - 4 true? Is -2 ≥ -9 true? Yes. Thus, (5,-2) satisfies both inequalities and is thus another solution.
Check out (-5,2) and (-5,-2) in precisely the same way. Is either one, or are both, a solution (or solutions) to the given set of inequalities?
Answer:
Step-by-step explanation:
First, the acceleration of gravity is -9.8m/s^2. This still works out since the formula uses 1/2 of it.
Hopefully you see where the other parts come from. Anyway, standard form of a quadratic is ax^2+bx+c=0. So this is almost there. You just need to subtract that 2.1 from both sides.
-4.9t^2+7.5t+-.3=0
Now with this, since it has taken into account the height that the ball was caught with that 2.1, you just need to find the 0s, which is what the quadratic equation does.
The quadratic equation is (-b±sqrt(b^2-4ac))/(2a) and we have a = -4.9, b = 7.5 and c = -.3. Remember you want to keep the signs. Now we just plug in.
(-b±sqrt(b^2-4ac))/(2a)
(-7.5±sqrt((-7.5)^2-4*-4.9*-.3))/(2*-4.9)
(-7.5±sqrt(56.25-5.88))/(.9.8)
(-7.5±sqrt(50.37))/(-9.8)
(-7.5±7.097)/(-9.8)
The plus or minus means there are two equations.
(-7.5+7.097)/(-9.8) and (-7.5-7.097)/(-9.8) So we will solve for both of these.
.04112 and 1.4895. That means these two times are when the ball is at 2.1 meters. One time on the way up and one time on the way down. We can safely assume that the other player catches the ball on the way down, so we want to use the second time, so 1.4895 seconds.
