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Nat2105 [25]
3 years ago
14

For the function, f(x) = -3x + 5. If f(x) = -1, what is the value of x?

Mathematics
1 answer:
Archy [21]3 years ago
6 0

Remember the f(x) is the same thing as y so...

y = -3x + 5

y = -1

To solve this plug -1 in for y in the equation y = -3x + 5 and solve for x

-1 = -3x + 5

-6 = -3x

2 = x

When f(x) is -1 then x is 2

Hope this helped!

~Just a girl in love with Shawn Mendes

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This = P(message is from Steven) =  number of messages from steven / total number of messages  from previous night

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100 points!! Brainliest if correct!!
Elena-2011 [213]

surface area (S) of a right rectangular solid is:

S = 2*L*W + 2*L*H + 2*W*H (equation 1)

where:

L = length

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you have:

L = 7

W = a

H = 4

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formula becomes:

S = 2*7*a + 2*7*4 + 2*a*4

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combine like terms:

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answer is:

S = 22*a + 56 (equation 2)

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to prove, substitute any value for a in equation 2:

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S = 22*15 + 56

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since a = 15, then W = 15 because W = a

go back to equation 1 and substitute 15 for W:

S = 2*L*W + 2*L*H + 2*W*H (equation 1)

where:

L = length

W = width

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you have:

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equation 1 becomes:

S = 2*7*15 + 2*7*4 + 2*15*4

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S = 210 + 56 + 120

S = 386

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surface area is the same using both equations so:

equations are good.

formula for surface area of right rectangle in terms of a is:

S = 22*a + 56

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9 down, 5 right, compression by factor of 2, reflection across the x- axis

Step-by-step explanation:

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3 years ago
A bag contain 3 black balls and 2 white balls.
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Answer:

Step-by-step explanation:

Total number of balls = 3 + 2 = 5

1)

a)

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b)

Probability \ of \ one \ black \ and \ one\ white \ with \ replacement \\\\= \frac{3C_1}{5C_1} \times \frac{2C_1}{5C_1} = \frac{3}{5} \times \frac{2}{5} = \frac{6}{25}

c)

Probability of at least one black( means BB or BW or WB)

 =\frac{3}{5} \times \frac{3}{5} + \frac{3}{5} \times \frac{2}{5} + \frac{2}{5} \times \frac{3}{5} \\\\= \frac{9}{25} + \frac{6}{25} + \frac{6}{25}\\\\= \frac{21}{25}

d)

Probability of at most one black ( means WW or WB or BW)

=\frac{2}{5} \times \frac{2}{5} + \frac{3}{5} \times \frac{2}{5} \times \frac{2}{5} + \frac{3}{5}\\\\= \frac{4}{25} + \frac{6}{25} + \frac{6}{25}\\\\=\frac{16}{25}

2)

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b) Probability  of one black and one white

 =\frac{3}{5} \times \frac{2}{4}\\\\=\frac{6}{20}\\\\=\frac{3}{10}

c) Probability of at least one black ( BB or BW or WB)

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d) Probability of at most one black ( BW or WW or WB)

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