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Liono4ka [1.6K]
4 years ago
13

Chef Johnson used 4 1/2 cups of flour to make 4 fruit cakes how many cups of flour are needed for 1 cake

Mathematics
1 answer:
Fynjy0 [20]4 years ago
3 0

let's firstly convert the mixed fraction to an improper fraction.


\bf \stackrel{mixed}{4\frac{1}{2}}\implies \cfrac{4\cdot 2+1}{2}\implies \stackrel{improper}{\cfrac{9}{2}} \\\\[-0.35em] ~\dotfill\\\\ \begin{array}{ccll} \stackrel{flour}{cups}&\stackrel{fruit}{cake}\\ \cline{1-2}\\ \frac{9}{2}&4\\[1em] x&1 \end{array}\implies \cfrac{~~\frac{9}{2}~~}{x}=\cfrac{4}{1}\implies \cfrac{~~\frac{9}{2}~~}{\frac{x}{1}}=\cfrac{4}{1}\implies \cfrac{9}{2}\cdot \cfrac{1}{x}=4 \\\\\\ \cfrac{9}{2x}=4\implies 9=8x\implies \cfrac{9}{8}=x\implies 1\frac{1}{8}=x

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The great Pyramid outside Cairo, Egypt, has a square base measuring 756 feet on a side and a height of 480ft
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Answer:

V = 3,386,880 cubic yards

V = 91445760 cubic feet

V = (1/3) · b2 · h  so  1/3  x 756^2 x 480 = 91445760 ft^3

Answer = 91445760 ft^3

Step-by-step explanation:

converting feet into yards

let  

1 yard = 3 ft  

1 ft = (1/3) yard  

a = 756 ft = 756*(1/3) yards the length of the side of the square base

h = 480 ft = 480*(1/3) yards the height of the pyramid

 

a.) the volume of the pyramid V = (a^2*h)/3 = (a^2*h)(1/3)

V = (756*(1/3))^2*480*(1/3)*(1/3)

V = 3,386,880 cubic yards

7 0
2 years ago
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right angle

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6 0
3 years ago
Which system of inequalities is represented by the graph?
sergey [27]
I believe the correct answer is the third answer.

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7 0
4 years ago
Read 2 more answers
X/-10 -4 = 16 what's the compute ?
grin007 [14]

Answer:

x=-200

Step-by-step explanation:

x/-10 -4 = 16

Add 4 to each side

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Multiply each side by -10

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4 0
3 years ago
Please help! Correct answer only, please!
sukhopar [10]

Answer: A. \left[\begin{array}{ccc}29&13\\13&10\\\end{array}\right]

Step-by-step explanation:

The question is asking us to find the product of the matrices. The key difference is the second A has a little <em>T</em> in the exponent. This <em>T</em> means transpose. You multiply A by the transpose of A. To find the transpose, you turn the rows into columns.

A^T=\left[\begin{array}{ccc}5&3\\2&-1\\\end{array}\right]

Now that we have our transpose, we can multiply the matrices.

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4 0
3 years ago
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