First we use product rule
y=x^2lnx
dy/dx = x^2 d/dx (lnx) + lnx d/dx (x^2)
dy/dx = x^2 (1/x) + lnx (2x)
dy/dx = x + 2xlnx
now taking second derivative:
d2y/dx2 = 1 + 2[x (1/x) + lnx (1)]
d2y/dx2 = 1 + 2[1+lnx]
1+2+2lnx
3+2lnx is the answer
Yes, HL would be correct.
This states that if two hypotenuses are congruent (they have the same one)
and if one pair of legs are congruent,
the figure is congruent.
I hope this helps!
~cupcake
Answer: May you show the angle we are supposed to solve? its a bit unclear. or can you explain the angle to us?
Step-by-step explanation:
6/(x-8)=2/(x+6)
times both sides by (x-8)(x+6)
6(x+6)=2(x-8)
distribute
6x+36=2x-16
minus 2x both sides
4x+36=-16
miinus 36 both sides
4x=-52
divide both sides by 4
x=-13
Answer:
<h2><u>0</u></h2>
Step-by-step explanation:
If 2u-6=4, let's solve for u.
Add 6 to both sides
2u-6+6 = 4+6
Simplify
2u = 10
Divide both sides by 2
u = 5
Now, we can solve u-5
5-5 = 0
