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3 years ago

3 liters = _____ milliters

Mathematics

1 answer:

DiKsa [7]3 years ago

5 0

3000 milliters hope this helps

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Pls answer this question correctly and I will mark it has brainlist please

densk [106]

Answer:

18.5

Step-by-step explanation:

First find the area of the two triangles.

1.5 * 1.5 = 2.25

Find the area of the two top rectangles: 2.5 * 1.7 * 2 = 8.5

Finally, find the area of the floor: 1.5 * 2.5 = 3.75

2.25 + 8.5 + 7.75 = 18.5

6 0

3 years ago

PLEASE ANSWER ASAP FOR BRAINLEST!!!!!!!!!!!!!!!!

77julia77 [94]

Answer:

$125

Step-by-step explanation:

To solve this, we need to find 2.5% of 5,000. To do this, we multiply 5,000 by .025. This gets us 125. That means you earn $125 worth of interest in one year.

7 0

3 years ago

Read 2 more answers

Simplify.<br><br> (-7p)3<br><br> please help

OleMash [197]

Answer:

-343p^3

Step-by-step explanation:

This is the answer because -7x-7x-7 would be -343 and you MUST keep the negative sign. The p x pxp would be p^3

Multiply the numbers:

-343p^3 would be your answer

Hope this helps!! :D

8 0

3 years ago

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Evaluate the line integral, where c is the given curve. (x + 9y) dx + x2 dy, c c consists of line segments from (0, 0) to (9, 1)

viktelen [127]

$\displaystyle\int_C(x+9y)\,\mathrm dx+x^2\,\mathrm dy=\int_C\langle x+9y,x^2\rangle\cdot\underbrace{\langle\mathrm dx,\mathrm dy\rangle}_{\mathrm d\mathbf r}$

The first line segment can be parameterized by $\mathbf r_1(t)=\langle0,0\rangle(1-t)+\langle9,1\rangle t=\langle9t,t\rangle$ with $0\le t\le1$ . Denote this first segment by $C_1$ . Then

$\displaystyle\int_{C_1}\langle x+9y,x^2\rangle\cdot\mathbf dr_1=\int_{t=0}^{t=1}\langle9t+9t,81t^2\rangle\cdot\langle9,1\rangle\,\mathrm dt$
$=\displaystyle\int_0^1(162t+81t^2)\,\mathrm dt$
$=108$

The second line segment ( $C_2$ ) can be described by $\mathbf r_2(t)=\langle9,1\rangle(1-t)+\langle10,0\rangle t=\langle9+t,1-t\rangle$ , again with $0\le t\le1$ . Then

$\displaystyle\int_{C_2}\langle x+9y,x^2\rangle\cdot\mathrm d\mathbf r_2=\int_{t=0}^{t=1}\langle9+t+9-9t,(9+t)^2\rangle\cdot\langle1,-1\rangle\,\mathrm dt$
$=\displaystyle\int_0^1(18-8t-(9+t)^2)\,\mathrm dt$
$=-\dfrac{229}3$

Finally,

$\displaystyle\int_C(x+9y)\,\mathrm dx+x^2\,\mathrm dy=108-\dfrac{229}3=\dfrac{95}3$

5 0

3 years ago

Ill mark brainlist plss help

Crazy boy [7]

Answer: 200km

Step-by-step explanation:

200 mm and 200cm are too small.

4 0

3 years ago

Read 2 more answers