Answer:
Step-by-step explanation:
Hello!
The variable of interest is
X: the amount a 10-11-year-old spends on a trip to the mall.
Assuming that the variable has a normal distribution, you have to construct a 98% CI for the average of the amount spent by the 10-11 year-olds on one trip to the mall.
For this you have to use a Student-t for one sample:
X[bar] ± *
n= 6
$18.31, $25.09, $26.96, $26.54, $21.84, $21.46
∑X= 140.20
∑X²= 3333.49
X[bar]= ∑X/n= 140.20/6= 23.37
S²= 1/(n-1)*[∑X²-(∑X)²/n]= 1/5[3333.49-(140.2)²/6]= 11.50
S= 3.39
X[bar] ± *
[23.37 ± 3.365 * ]
[18.66;29.98]
With a confidence level of 98%, you'd expect that the interval $[18.66;29.98] will include the population mean of the money spent by 10-11 year-olds in one trip to the mall.
I hope you have a SUPER day!
Answer:
The greatest common factor is 8.
Step-by-step explanation:
You can evenly split 8 and 48 into 8.
I hope i helped.
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Answer:
78.5
Step-by-step explanation:
.....ur welcome.........
3.14×5²
Answer:
B. 11√2
Step-by-step explanation:
Those marks on the lines mean the side's length is 11. Now to solve x we use the Pythagorean thereom.
11^2+11^2=x^2
x^2=242
x=11√2
The barometric pressure is 30.42 - measured by inch of mercury units - and is falling since its last observation.