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3 years ago

9

Which point could be removed in order to make the relation a function?

2 answers:

ki77a [65]3 years ago

7 0

<h3><em>The answer is (-4,5) which is C</em></h3><h3><em>I hope this is helpful xD :)</em></h3>

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zepelin [54]3 years ago

5 0

For a set to be a function, there can be no repeating x-values. Therefore, the answer is (-4,5), because the input value "-4" has two different output values.

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There is an outbuilding that has an area of 80 square feet. The rectangle on the blueprint that represents the outbuilding has a

Tanya [424]

Answer:

B) 4

Step-by-step explanation:

There is an outbuilding that has an area of 80 square feet. The rectangle on the blueprint that represents the outbuilding has an area of 20 square inches. If the actual outbuilding has a wall length of 10 feet, what is the length of that wall on the blueprint . A) 3 B) 4 C) 5 D) 6

The length of the wall on the blue print can be calculated as:

20 square feet ÷ 5

= 4 feet

8 0

3 years ago

The coordinates of the endpoints of AB and CD are A(2,

Ratling [72]

Answer:

Option 1: CD is a perpendicular bisector of AB

Step-by-step explanation:

Let us find out the slopes of various line segments and the Distances and then we will draw the conclusions accordingly.

Formula to find slope

$m= \frac{y_2-y_1}{x_2-x_1}$

Formula to Find Distance between two points

$D=\sqrt{(y_2-y_1)^2+(x_2-x_1)^2}$

mAB ( represents , Slope of AB )

1. $mAC= \frac{3-2}{2-5}=\frac{1}{-3}=-\frac{1}{3}$

2. $mBC=\frac{2-1}{5-8}=\frac{1}{-3}=-\frac{1}{3}$

3. $mCD=\frac{5-2}{6-5}=\frac{3}{1}=3$

4. $AC=\sqrt{(3-2)^2+(2-5)^2} =\sqrt{(1)^2+(-3)^2}=\sqrt{1+9}=\sqrt{10}$

5. $BC=\sqrt{(2-1)^2+(5-8)^2} =\sqrt{(1)^2+(-3)^2}=\sqrt{1+9}=\sqrt{10}$

mAC = mBC , and C is common point , hence these three are collinear points making a straight line whole slope is $-\frac{1}{3}$

$mAB=-\frac{1}{3}$

$mCD=3$

$mAB \times mCD = -\frac{1}{3} \times 3 = -1$

Hence CD ⊥ AB

Also

From Point 4 and point 5 above , we see that

AC = CB

Hence CD bisect AB at C, also CD ⊥ AB

There fore

CD is a perpendicular bisector of AB

Therefor option 1 is true

4 0

3 years ago

Reflect AQ'R'S' if Q'(1, -3), R'(-2,-6),<br> and S'(-1,-1) over the x-axis.

castortr0y [4]

Answer:

Step-by-step explanation:

The rule of reflecting over the x-axis is that point (x, y) →( x, -y) so

Q'(1, -3), R'(-2,-6),and S'(-1,-1) reflected over the x-axis, become

Q"(1, 3), R"(-2, 6), and S"(-1, 1) .

6 0

2 years ago

Find mFE<br> A) 52°<br> C) 76°<br> B) 93°<br> D) 112°

mixer [17]

Answer:

76 degrees

Step-by-step explanation:

GE = 180 since it is a straight line

GE = GR + FE

180 = 7x+6 +6x-8

Combine like terms

180 = 13x-2

Add 2 to each side

182 = 13x

Divide by 13

182/13 = 13x/13

14 =x

We want FE

FE = 6x-8

FE = 6(14) -8

=84 -8

=76

3 0

3 years ago

Please help for brainliest.

Kaylis [27]

Answer:

its C

Step-by-step explanation:

7 0

3 years ago