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3 years ago

7

What is the value of x? Round your answer to the nearest tenth if necessary.

1 answer:

Blizzard [7]3 years ago

8 0

By the Pythagorean Theorem, x^2+14^2=20^2, so x^2+196=400, so x^2=204. Then, x=sqrt(204)~=14.3.

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What is the length of the diagonal of a rectangle

Fed [463]

A diagonal of a rectangle cuts the rectangle into 2 right triangles with sides equal to the sides of the rectangle and with a hypotenuse that is the diagonal. All you need to do is use the pythagorean theorem: where a and b are the sides of the rectangle and c is the length of the diagonal.

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3 years ago

What is an equation of the line that passes

sasho [114]

2x-2y

parallel means that the x part is the same

and it is -2y because the y-coordinate is -2

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2 years ago

ABC and ADC are triangles.

nadya68 [22]

Answer:you have do your know work kid no one is going to help you other than your teacher.

Step-by-step explanation:

Ask your teacher for help.

7 0

3 years ago

Helen borrowed money from her aunt to pay for college expenses. The graph below shows the amount left

enot [183]

Answer:

$y = -100x + 13000$

Step-by-step explanation:

See attachment for graph

First, we need to take any corresponding values of x and y

$(x_1,y_1) = (0,13000)$

$(x_2,y_2) = (130,0)$

Next, we calculate the slope (m)

$m = \frac{y_2 - y_1}{x_2 - x_1}$

$m = \frac{0 - 13000}{130 - 0}$

$m = \frac{- 13000}{130}$

$m = -100$

Next, we calculate the line equation using:

$y - y_1=m(x-x_1)$

$y - 13000 = -100(x - 0)$

$y - 13000 = -100x$

Make y the subject

$y = -100x + 13000$

Hence, the line equation is:

$y = -100x + 13000$

4 0

3 years ago

A survey of households revealed that 38% have a dog, 47% have a cat, and 15% have both a cat and a dog.

coldgirl [10]

Answer:

I) P(cat│dog) = $\frac{0.15}{0.38}$

II) These events are not independent

III) P(cat or dog)= 0.7

Step-by-step explanation:

Given : Households have dogs = 38%

So, P(dog) = 0.38

Households have cats = 47%

So, P(cats) = 0.47

Households have both dogs and cats = 15%

So, P(both dog and cat ) = $P(cat\cap dog)$ = 0.15

solution :

i) By formula P(A│B) = $\frac{P(A\cap B)}{P(B)}$

P(cat│dog)= $\frac{P(cat\cap dog)}{P(dog)}$

P(cat│dog) = $\frac{0.15}{0.38}$

ii) P(cat│dog)=39.47% = 0.39 and P(cat)=47% = 0.47, are the events not independent

Because condition for independent events in conditional probability is P(A|B)=P(A)

but P(cat│dog) ≠P(cat) i.e. 0.39≠0.47

So, these events are not independent

iii) P(cat or dog) = ?

"or" means union

Formula : $P(A\cup B)= P(A) + P(B)-P(A\cap B)$

P(cat or dog) = $P(cat\cup dog)= P(cat) + P(dog)-P(cat\cap dog)$

P(cat or dog)= 0.47 + 0.38 - 0.15

P(cat or dog)= 0.7

6 0

3 years ago

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