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Svet_ta [14]
3 years ago
13

HELP PLS idk how to do this It's called Project: Let's get cooking!

Mathematics
1 answer:
Anastaziya [24]3 years ago
4 0

Answer: What exactly do you need help with

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A box in the shape of a right rectangular
Ostrovityanka [42]

Answer:

96 inches cubed

Step-by-step explanation:

3*4*8=96

6 0
3 years ago
PLEASE HELP! I'LL GIVE BRAINLIEST:)
Taya2010 [7]

Step-by-step explanation:

We know that if (h,k) is the center of any circle and whose radius is = r then its equation is :

{(x - h)}^{2}  +  {(y - k)}^{2}  =  {r}^{2}

Given, the equation of circle

{(x + 2)}^{2}  + (y - 3) ^{2}  = 25 =  {5}^{2}

By comparing, we will get,

h = -2

k = 3

So, center of the circle is ( -2,3)

\large \green{  \:  \:  \:  \:  \boxed{\boxed{\begin{array}{cc} \bf\:Mark\\\bf\:me\:as\\\bf brainliest \end{array}}}} \\

5 0
3 years ago
Read 2 more answers
A lifeguard is in a look out chair and sees a person in distress. The eye level of the lifeguard is 15 feet above the ground. Th
faltersainse [42]

Answer:

Horizontal distance between lifeguard and the person is 22 feet.

Step-by-step explanation:

Given: A lifeguard sees a person in distress.The eye level of the lifeguard is 15 feet above the ground. Angle of depression is 34°.

To find: Horizontal distance between lifeguard and the person.

Solution : If we draw a triangle then tan∅ = \frac{height}{base}

               Here base is the horizontal distance.

               Now we put the values in the formula.

               tan 34° = \frac{15}{base}

              Or Base = \frac{15}{tan34}

                             = \frac{15}{0.675} = 22.22 feet

So the answer is 22 feet.

7 0
3 years ago
Fine length of BC on the following photo.
MrMuchimi

Answer:

BC=4\sqrt{5}\ units

Step-by-step explanation:

see the attached figure with letters to better understand the problem

step 1

In the right triangle ACD

Find the length side AC

Applying the Pythagorean Theorem

AC^2=AD^2+DC^2

substitute the given values

AC^2=16^2+8^2

AC^2=320

AC=\sqrt{320}\ units

simplify

AC=8\sqrt{5}\ units

step 2

In the right triangle ACD

Find the cosine of angle CAD

cos(\angle CAD)=\frac{AD}{AC}

substitute the given values

cos(\angle CAD)=\frac{16}{8\sqrt{5}}

cos(\angle CAD)=\frac{2}{\sqrt{5}} ----> equation A

step 3

In the right triangle ABC

Find the cosine of angle BAC

cos(\angle BAC)=\frac{AC}{AB}

substitute the given values

cos(\angle BAC)=\frac{8\sqrt{5}}{16+x} ----> equation B

step 4

Find the value of x

In this problem

\angle CAD=\angle BAC ----> is the same angle

so

equate equation A and equation B

\frac{8\sqrt{5}}{16+x}=\frac{2}{\sqrt{5}}

solve for x

Multiply in cross

(8\sqrt{5})(\sqrt{5})=(16+x)(2)\\\\40=32+2x\\\\2x=40-32\\\\2x=8\\\\x=4\ units

DB=4\ units

step 5

Find the length of BC

In the right triangle BCD

Applying the Pythagorean Theorem

BC^2=DC^2+DB^2

substitute the given values

BC^2=8^2+4^2

BC^2=80

BC=\sqrt{80}\ units

simplify

BC=4\sqrt{5}\ units

7 0
3 years ago
To rent a moving truck for the day, it costs $33 plus $1 for each mile driven. Write an expression for the total cost to rent th
alina1380 [7]

Answer:

Step-by-step explanation:

7 0
3 years ago
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