HELP PLS<br> idk how to do this<br> It's called Project: Let's get cooking!

A box in the shape of a right rectangular

Ostrovityanka [42]

Answer:

96 inches cubed

Step-by-step explanation:

3*4*8=96

6 0

3 years ago

PLEASE HELP! I'LL GIVE BRAINLIEST:)

Taya2010 [7]

Step-by-step explanation:

We know that if (h,k) is the center of any circle and whose radius is = r then its equation is :

${(x - h)}^{2} + {(y - k)}^{2} = {r}^{2}$

Given, the equation of circle

${(x + 2)}^{2} + (y - 3) ^{2} = 25 = {5}^{2}$

By comparing, we will get,

h = -2

k = 3

So, center of the circle is ( -2,3)

$\large \green{ \: \: \: \: \boxed{\boxed{\begin{array}{cc} \bf\:Mark\\\bf\:me\:as\\\bf brainliest \end{array}}}} \\$

5 0

3 years ago

Read 2 more answers

A lifeguard is in a look out chair and sees a person in distress. The eye level of the lifeguard is 15 feet above the ground. Th

faltersainse [42]

Answer:

Horizontal distance between lifeguard and the person is 22 feet.

Step-by-step explanation:

Given: A lifeguard sees a person in distress.The eye level of the lifeguard is 15 feet above the ground. Angle of depression is 34°.

To find: Horizontal distance between lifeguard and the person.

Solution : If we draw a triangle then tan∅ = $\frac{height}{base}$

Here base is the horizontal distance.

Now we put the values in the formula.

tan 34° = $\frac{15}{base}$

Or Base = $\frac{15}{tan34}$

= $\frac{15}{0.675} = 22.22 feet$

So the answer is 22 feet.

7 0

3 years ago

Fine length of BC on the following photo.

MrMuchimi

Answer:

$BC=4\sqrt{5}\ units$

Step-by-step explanation:

see the attached figure with letters to better understand the problem

step 1

In the right triangle ACD

Find the length side AC

Applying the Pythagorean Theorem

$AC^2=AD^2+DC^2$

substitute the given values

$AC^2=16^2+8^2$

$AC^2=320$

$AC=\sqrt{320}\ units$

simplify

$AC=8\sqrt{5}\ units$

step 2

In the right triangle ACD

Find the cosine of angle CAD

$cos(\angle CAD)=\frac{AD}{AC}$

substitute the given values

$cos(\angle CAD)=\frac{16}{8\sqrt{5}}$

$cos(\angle CAD)=\frac{2}{\sqrt{5}}$ ----> equation A

step 3

In the right triangle ABC

Find the cosine of angle BAC

$cos(\angle BAC)=\frac{AC}{AB}$

substitute the given values

$cos(\angle BAC)=\frac{8\sqrt{5}}{16+x}$ ----> equation B

step 4

Find the value of x

In this problem

$\angle CAD=\angle BAC$ ----> is the same angle

so

equate equation A and equation B

$\frac{8\sqrt{5}}{16+x}=\frac{2}{\sqrt{5}}$

solve for x

Multiply in cross

$(8\sqrt{5})(\sqrt{5})=(16+x)(2)\\\\40=32+2x\\\\2x=40-32\\\\2x=8\\\\x=4\ units$

$DB=4\ units$

step 5

Find the length of BC

In the right triangle BCD

Applying the Pythagorean Theorem

$BC^2=DC^2+DB^2$

substitute the given values

$BC^2=8^2+4^2$

$BC^2=80$

$BC=\sqrt{80}\ units$

simplify

$BC=4\sqrt{5}\ units$

7 0

3 years ago

To rent a moving truck for the day, it costs $33 plus $1 for each mile driven. Write an expression for the total cost to rent th

alina1380 [7]

Answer:

Step-by-step explanation:

7 0

3 years ago

HELP PLS idk how to do this It's called Project: Let's get cooking!