The sum of the 8 terms of the series 1-1-3-5- ... -13 is -48
The given sequence is:
1,-1,-3, . . -13
and there are 8 terms.
The related series of this sequence is:
1-1-3-5- ... -13
Notice that the series is an arithmetic series with:
first term, a(1) = 1
common difference, d = -1 - (1) = -2
last term, a(8) = -13
To find the sum of the series, use the sum formula:
S(n) = n/2 [(a(1) + a(n)]
Substitute n = 8, a(1) = 1, a(n) = a(8) = -13 into the formula:
S(8) = 8/2 [1 + (-13)]
S(9) = 4 . (-12) = -48
Learn more about sum of a series here:
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The isosceles trapezoid is part of an isosceles triangle with a 34 degree vertex angle. The measure of an acute base angle of the trapezoid is 73 degrees.
L + W
length plus width
example: L = 10" W = 20" 10 x 20 = 200
f(x) = (x- zero) * (x -zero)
f(x) = (x--2) (x-8)
f(x) = (x+2) (x-8)
if you need it multiplied out
f(x) = x^2 +2x -8x-16
f(x) = x^2 -6x-16
Answer:
x = 9
Step-by-step explanation:
110 + 3x + 11 = 16x + 4
121 + 3x = 16x + 4
<u> -3x -3x</u>
121 = 13x + 4
<u>-4 - 4</u>
117 = 13x
117 ÷ 13 = x
9 = x
Check:
110 + 3(9) + 11 = 16(9) + 4
121 + 27 = 144 + 4
148 = 148
