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Sergio039 [100]
3 years ago
15

What is the change in temperature from 15 degrees to -9 degrees? -6, 6, -24, 25

Mathematics
1 answer:
dalvyx [7]3 years ago
3 0

Answer:

24 degrees

Step-by-step explanation:

The distance from 15 degrees to 0 degrees is 15, and the distance from 0 degrees to -9 degrees is 9, so then the total distance from 15 degrees to -9 degrees is (15+9 degrees) which adds up to be 24 degrees

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When the velocity v of an object is very​ large, the magnitude of the force due to air resistance is proportional to v squared w
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Answer:

Step-by-step explanation:

The model fo the shell is given by the following equation of equilibrium:

\Sigma F = -b\cdot v^{2} - m\cdot g = m\cdot \frac{dv}{dt}

This first-order differential equation has separable variables, which are cleared herein:

\int\limits^t_{0\,s} \, dt = -\frac{m}{b} \int\limits^{0\,\frac{m}{s} }_{600\,\frac{m}{s} } {\frac{1}{ v^{2}+\frac{m}{b}\cdot g } } \, dv

The solution of this integral is:

t = -\frac{m}{2b}\cdot \left[\tan^{-1} \left(\frac{v}{\sqrt{\frac{m\cdot g}{b} } }\right) - \tan^{-1} \left(\frac{600}{\sqrt{\frac{m\cdot g}{b} } }\right)\right]

\tan^{-1} \left(\frac{v}{\sqrt{\frac{m\cdot g}{b} } }  \right)=-\frac{2\cdot b\cdot t}{m} + \tan^{-1}\left(\frac{600}{\sqrt{\frac{m\cdot g}{b} } }  \right)

\frac{v}{\sqrt{\frac{m\cdot g}{b} } }=\tan \left[-\frac{2\cdot b\cdot t}{m} + \tan^{-1}\left(\frac{600}{\sqrt{\frac{m\cdot g}{b} } }  \right)\right]

v = \sqrt{\frac{m\cdot g}{b} } \left [\frac{\tan \left(-\frac{2\cdot b \cdot t}{m}  \right)+ \left(\frac{600}{\sqrt{\frac{m\cdot g}{b} } }  \right)}{1 - \left(\frac{600}{\sqrt{\frac{m\cdot g}{b} } }  \right)\cdot \tan \left(-\frac{2\cdot b \cdot t}{m}  \right) }\right]

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Answer:

¼ x 20 = 5

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Step-by-step explanation:

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table B

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