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4 years ago

Use the properties above to simplify each expression.

Mathematics

1 answer:

Studentka2010 [4]4 years ago

8 0

Step-by-step explanation:

9. 27+7x

10.52x+8

forgive me if im wrong but I'm sure it's that

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John's boss asks him on Friday to work Saturday, he has already worked 40 hours this

padilas [110]

Answer:

$162.64

Step-by-step explanation:

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3 years ago

Given the slopes of three lines, m1 = 2, m2 = 5. m3 = -4, which line would you say is

bagirrra123 [75]

Compare the slopes of the 4 equations, which is the number in the term with "x". The slope with highest absolute value is the steepest. Positive slope means the function is ascending left to right, negative slope means it is descending left to right. If you only care that it is the steepest, regardless of whether it is ascending or descending, then the answer is (D).

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2 years ago

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A hiking trail is 5,000 meters long. what is the length in kilometers?

Oxana [17]

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3 years ago

Solve the system using addition. Use pencil and paper. Explain why the addition method is a good choice for solving the system.

raketka [301]

Answer:

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Step-by-step explanation:

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3 years ago

What is the zero in the quadratic function f(x)= 9x^2-54x-19?

Alex17521 [72]

Answer:

6.33... and 0.333...

Step-by-step explanation:

The quadratic formula is

$x=\frac{-b+\sqrt{b^2-4ac} }{2a}$ .

It is important because while some quadratics are factorable and can be solved not all are. The formula will solve all quadratic equations and can also give both real and imaginary solutions. Using the formula will require less work than finding the factors if factorable. We will substitute a=9, b=-54 and c=-19.

$x=\frac{-b+/-\sqrt{b^2-4ac} }{2a}\\x=\frac{-(-54)+/-\sqrt{(-54)^2-4(9)(-19)} }{2(9)}\\x=\frac{54+/-\sqrt{2916+684} }{18}$

We will now solve for the plus and the minus.

The plus,,,

$x=\frac{54+\sqrt{3600}}{18}\\x=\frac{54+60}{18}\\x=\frac{114}{18}\\x=6.3$

and the minus...

$x=\frac{54-\sqrt{3600}}{18}\\x=\frac{54-60}{18}\\x=\frac{-6}{18}\\x=-0.333...$

8 0

4 years ago