A package weighs 4.25 kilograms. How many grams does the package weigh?(Please Show Work :D)

If there is a 1.3 ratio of river to ocean dragons, and there are 12 ocean dragons,how many river dragons will you have

dalvyx [7]

Answer:

4 river dragons

Step-by-step explanation:

1 : 3 = x : 12

(1 x 4) : (3 x 4) = x : 12

4 : 12 = x : 12

x = 4

5 0

3 years ago

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1. Verizon Wireless would like to estimate the proportion of households that use cell phones for their phone service without a l

Pavel [41]

Answer:

The 95% confidence interval for the true proportion of households which rely strictly on cell phones for their phone serviceis (0.2453, 0.3947).

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of $\pi$ , and a confidence level of $1-\alpha$ , we have the following confidence interval of proportions.

$\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}$

In which

z is the zscore that has a pvalue of $1 - \frac{\alpha}{2}$ .

A random sample of 150 households was selected and 48 relied strictly on cell phones for their service.

This means that $n = 150, \pi = \frac{48}{150} = 0.32$

95% confidence level

So $\alpha = 0.05$ , z is the value of Z that has a pvalue of $1 - \frac{0.05}{2} = 0.975$ , so $Z = 1.96$ .

The lower limit of this interval is:

$\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.32 - 1.96\sqrt{\frac{0.32*0.68}{150}} = 0.2453$

The upper limit of this interval is:

$\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.32 + 1.96\sqrt{\frac{0.32*0.68}{150}} = 0.3947$

The 95% confidence interval for the true proportion of households which rely strictly on cell phones for their phone serviceis (0.2453, 0.3947).

5 0

3 years ago

Which ratio represents cos C? A) 8 17 B) 8 15 C) 15 17 D) 17 15

Arturiano [62]

Took the quiz myself, 15/17 is the answer.

7 0

3 years ago

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Can anyone answer and explain??

Ad libitum [116K]

Answer:

i tried to answer it but it wont let me

Step-by-step explanation:

5 0

3 years ago

A(7-1), B(6, 4) and C(5, 5) are three

Andrej [43]

Answer:

The answer is below

Step-by-step explanation:

The equation of the line passing through two points is given by:

$y-y_1=\frac{y_2-y_1}{x_2-x_1}(x-x_1)\\$

The equation of line AB is:

$y-y_1=\frac{y_2-y_1}{x_2-x_1}(x-x_1)\\\\y-(-1)=\frac{4-(-1)}{6-7}(x-7)\\\\y+1=-5(x-7)\\y+1=-5x+35\\y=-5x+34$

The midpoint of two lines is given as:

$x=\frac{x_1+x_2}{2}, y=\frac{y_1+y_2}{2}\\midpoint\ of\ AB \ is:\\x=\frac{7+6}{2}=6.5, y=\frac{-1+4}{2}=1.5\\ = (6.5,1.5)$

The equation of line AC is:

$y-y_1=\frac{y_2-y_1}{x_2-x_1}(x-x_1)\\\\y-(-1)=\frac{5-(-1)}{5-7}(x-7)\\\\y+1=-3(x-7)\\y+1=-3x+21\\y=-3x+20$

The midpoint of two lines is given as:

$x=\frac{x_1+x_2}{2}, y=\frac{y_1+y_2}{2}\\midpoint\ of\ AB \ is:\\x=\frac{7+5}{2}=6, y=\frac{-1+5}{2}=2\\ = (6,2)$

The product of the slope of a perpendicular bisector of a line and the slope of the line is -1. That is m1m2 = -1

The slope of the perpendicular bisector of AB is:

m(-5)=-1

m=1/5

The equation of the perpendicular bisector of AB passing through (6.5,1.5) is:

$y-y_1=m(x-x_1)\\y-1.5=\frac{1}{5}(x-6.5)\\y=\frac{1}{5} x-8.25$

The slope of the perpendicular bisector of AB is:

m(-3)=-1

m=1/3

The equation of the perpendicular bisector of AB passing through (6,2) is:

$y-y_1=m(x-x_1)\\y-2=\frac{1}{3}(x-7)\\y=\frac{1}{3} x-4.33$

2) The point of intersection is gotten by solving y = 1/5 x -8.25 and y = 1/3 x-4.33 simultaneously.

Subtracting the two equations from each other gives:

0= -0.133x - 3.92

-0.133x = 3.92

x = -29.5

Put x = -29.5 in y = 1/5 x -8.25 i.e:

y = 1/5 (29.5) -8.25

y = -14.16

The point of intersection is (-29.5, -14.16)

4 0

3 years ago