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enyata [817]
4 years ago
12

Solve the following system of equations for X..

Mathematics
2 answers:
guajiro [1.7K]4 years ago
7 0

Answer:

x  =  3

Step-by-step explanation:

Solve for the first variable in one of the equations, then substitute the result into the other equation.

Fed [463]4 years ago
7 0
X would be -3so therefore it’s x-3
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9.If a = 1 + 3jand 5 = 27 + 1. Find the angle between aand b.​
Katarina [22]

Answer:Wrong

Step-by-step explanation:

7 0
3 years ago
Jonah and three of his friends are splitting the dinner bill equally among theme selves. There total bill came to be $86 before
Oksana_A [137]

Answer: Required expression: \dfrac{[ (86) + 0.18 \times(86 ) + 0.06 \times (86 )]}{4}

Each person need to pay =$ 26.66

Step-by-step explanation:

Given: Bill amount = $86

Tip percent = 18%

Sales tax = 6%

Now, total bill = (Bill amount ) + 18% of (Bill amount ) + 6% of (Bill amount )

=  $[ (86) + 18% of (86 ) + 6% of (86 )]

=  $[ (86) + 0.18 x(86 ) + 0.06 x (86 )]

Total persons = 3+1 = 4

Each person need to pay= \dfrac{\text{total bill}}{4}

=\dfrac{[ (86) + 0.18 \times(86 ) + 0.06 \times (86 )]}{4}\\\\=\dfrac{[ (86) (1+ 0.18  +0.06 )]}{4}\\\\=\dfrac{86(1.24)}{4}=\dfrac{106.64}{4}=26.66

So, each person need to pay =$ 26.66

4 0
3 years ago
Please answer (NO SPAMMING) What is the sum of 56.4t + 1650kg? Give your answer in Kg
Aliun [14]

Answer:1,706

Step-by-step explanation:

Add

7 0
3 years ago
Read 2 more answers
1) At AJ Welding Company they employ 253 people, 108 employees receive 2 weeks of paid 1) _______ vacation each year. Find the r
Fantom [35]

Answer:

108 : 145

Step-by-step explanation:

253 - 108 = 145

Ratio of those who receive 2 weeks of paid vacation is 108

Ratio of those paid vacation is not 2 weeks is 145

108 : 145

5 0
3 years ago
|2-5x|+3<10 how to solve
ivann1987 [24]
1 Simplify — 2 <span>Equation at the end of step  1  :</span> 2 3 1 ((— • x) - ——) - — = 0 5 10 2 <span> Step  2  :</span> 3 Simplify —— 10 <span>Equation at the end of step  2  :</span> 2 3 1 ((— • x) - ——) - — = 0 5 10 2 <span> Step  3  :</span> 2 Simplify — 5 <span>Equation at the end of step  3  :</span> 2 3 1 ((— • x) - ——) - — = 0 5 10 2 <span> Step  4  :</span>Calculating the Least Common Multiple :

<span> 4.1 </span>   Find the Least Common Multiple

      The left denominator is :      <span> 5 </span>

      The right denominator is :      <span> 10 </span>

<span><span>        Number of times each prime factor
        appears in the factorization of:</span><span><span><span> Prime 
 Factor </span><span> Left 
 Denominator </span><span> Right 
 Denominator </span><span> L.C.M = Max 
 {Left,Right} </span></span><span>5111</span><span>2011</span><span><span> Product of all 
 Prime Factors </span>51010</span></span></span>


      Least Common Multiple:
      10 

Calculating Multipliers :

<span> 4.2 </span>   Calculate multipliers for the two fractions


    Denote the Least Common Multiple by  L.C.M 
    Denote the Left Multiplier by  Left_M 
    Denote the Right Multiplier by  Right_M 
    Denote the Left Deniminator by  L_Deno 
    Denote the Right Multiplier by  R_Deno 

   Left_M = L.C.M / L_Deno = 2

   Right_M = L.C.M / R_Deno = 1

Making Equivalent Fractions :

<span> 4.3 </span>     Rewrite the two fractions into equivalent fractions

Two fractions are called equivalent if they have the same numeric value.

For example :  1/2   and  2/4  are equivalent, <span> y/(y+1)2  </span> and <span> (y2+y)/(y+1)3  </span>are equivalent as well.

To calculate equivalent fraction , multiply the Numerator of each fraction, by its respective Multiplier.

<span> L. Mult. • L. Num. 2x • 2 —————————————————— = —————— L.C.M 10 R. Mult. • R. Num. 3 —————————————————— = —— L.C.M 10 </span>Adding fractions that have a common denominator :

<span> 4.4 </span>      Adding up the two equivalent fractions
Add the two equivalent fractions which now have a common denominator

Combine the numerators together, put the sum or difference over the common denominator then reduce to lowest terms if possible:

2x • 2 - (3) 4x - 3 ———————————— = —————— 10 10 <span>Equation at the end of step  4  :</span> (4x - 3) 1 ———————— - — = 0 10 2 <span> Step  5  :</span>Calculating the Least Common Multiple :

<span> 5.1 </span>   Find the Least Common Multiple

      The left denominator is :      <span> 10 </span>

      The right denominator is :      <span> 2 </span>

<span><span>        Number of times each prime factor
        appears in the factorization of:</span><span><span><span> Prime 
 Factor </span><span> Left 
 Denominator </span><span> Right 
 Denominator </span><span> L.C.M = Max 
 {Left,Right} </span></span><span>2111</span><span>5101</span><span><span> Product of all 
 Prime Factors </span>10210</span></span></span>


      Least Common Multiple:
      10 

Calculating Multipliers :

<span> 5.2 </span>   Calculate multipliers for the two fractions


    Denote the Least Common Multiple by  L.C.M 
    Denote the Left Multiplier by  Left_M 
    Denote the Right Multiplier by  Right_M 
    Denote the Left Deniminator by  L_Deno 
    Denote the Right Multiplier by  R_Deno 

   Left_M = L.C.M / L_Deno = 1

   Right_M = L.C.M / R_Deno = 5

Making Equivalent Fractions :

<span> 5.3 </span>     Rewrite the two fractions into equivalent fractions

<span> L. Mult. • L. Num. (4x-3) —————————————————— = —————— L.C.M 10 R. Mult. • R. Num. 5 —————————————————— = —— L.C.M 10 </span>Adding fractions that have a common denominator :

<span> 5.4 </span>      Adding up the two equivalent fractions

(4x-3) - (5) 4x - 8 ———————————— = —————— 10 10 <span> Step  6  :</span>Pulling out like terms :

<span> 6.1 </span>    Pull out like factors :

   4x - 8  =   4 • (x - 2) 

<span>Equation at the end of step  6  :</span> 4 • (x - 2) ——————————— = 0 10 <span> Step  7  :</span>When a fraction equals zero :<span><span> 7.1 </span>   When a fraction equals zero ...</span>

Where a fraction equals zero, its numerator, the part which is above the fraction line, must equal zero.

Now,to get rid of the denominator, Tiger multiplys both sides of the equation by the denominator.

Here's how:

4•(x-2) ——————— • 10 = 0 • 10 10

Now, on the left hand side, the <span> 10 </span> cancels out the denominator, while, on the right hand side, zero times anything is still zero.

The equation now takes the shape :
   4  •  (x-2)  = 0

Equations which are never true :

<span> 7.2 </span>     Solve :    4   =  0

<span>This equation has no solution.
</span> A a non-zero constant never equals zero.

Solving a Single Variable Equation :

<span> 7.3 </span>     Solve  :    x-2 = 0<span> 

 </span>Add  2  to both sides of the equation :<span> 
 </span>                     x = 2

One solution was found :                   x = 2

<span>
</span>

4 0
3 years ago
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