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ioda
4 years ago
5

88% of 56.52 is what?

Mathematics
2 answers:
bonufazy [111]4 years ago
6 0
49.7376 is the answer you are looking for
Svetllana [295]4 years ago
3 0
49.7376

But if you round its

49.74
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23mm,20mm,13mm sides and 62,72,46, angle what type of triangle is that
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4 0
3 years ago
Find sec 2Theta in exact value
forsale [732]

Answer:

sec(2\theta)=-\frac{5}{4}

Step-by-step explanation:

we know that

step 1

Find cos(\theta)

we know that

tan^2(\theta)+1=sec^2(\theta)

we have

tan(\theta)=3

substitute

3^2+1=sec^2(\theta)

sec^2(\theta)=10

sec(\theta)=\pm\sqrt{10}

Remember that

Angle theta lie in Quadrant I

so

sec(\theta) is positive

sec(\theta)=\sqrt{10}

Remember that

sec(\theta)=\frac{1}{cos(\theta)}

therefore

cos(\theta)=\frac{1}{\sqrt{10}}

step 2

Find sin(\theta)

we know that

tan(\theta)=\frac{sin(\theta)}{cos(\theta)}

sin(\theta)=tan(\theta)cos(\theta)

we have

cos(\theta)=\frac{1}{\sqrt{10}}

tan(\theta)=3

substitute

sin(\theta)=(3)(\frac{1}{\sqrt{10}})

sin(\theta)=\frac{3}{\sqrt{10}}

step 3

Find cos(2\theta)

we know that

cos(2\theta)=2cos^2(\theta)-1

we have

cos(\theta)=\frac{1}{\sqrt{10}}

substitute

cos(2\theta)=2(\frac{1}{\sqrt{10}})^2-1

cos(2\theta)=\frac{1}{5}-1

cos(2\theta)=-\frac{4}{5}

Remember that

sec(2\theta)=\frac{1}{cos(2\theta)}

therefore

sec(2\theta)=-\frac{5}{4}

8 0
3 years ago
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