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Anton [14]
4 years ago
13

Which of these is the closest to DC, the height in feet,on the pole where the lower wire is attached ?

Mathematics
1 answer:
liq [111]4 years ago
5 0

Answer:

21.40 ft

Step-by-step explanation:

Angle BD is bisecting of ∠B, so we have to find ∠ B first. We have opposite(AC) and adjacent(BC) length, to find ∠B we can use tan formula.

tan ∠B= AC/BC

∠B= arctan(60ft/40ft)

∠B= 56.31 °

The ∠CBD bisect ∠B, so it equal to half of the angle. Angle CBD will be:

∠CBD= ∠B/2= 56.31 /2

∠CBD= 28.15 °

We have the angle(CBD) and adjacent(BC) length, now we can find DC using tan formula.

tan ∠CBD= DC/BC

DC= tan 28.15° * 40ft

DC= 0.53507226 * 40ft

DC= 21.40 ft

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Step-by-step explanation:

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3 years ago
The distance around a water fountain is 150 inches.What is the distance from the edge of the fountain to the center?
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The distance from the edge of the fountain to the centre is approximately 23.87 inches.

The water fountain forms a circle. The distance around the water fountain is the circumference of the circle formed.

Therefore,

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r = 75 / 3.14159

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r = 23.87 inches

The distance from the edge of the fountain to the centre is approximately 23.87 inches.

read more: brainly.com/question/23251242?referrer=searchResults

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3 years ago
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#33. WILL MEDAL pls help
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