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shtirl [24]
3 years ago
8

Liam had \$250$250dollar sign, 250. Then, he and his classmates bought a present for their teacher, evenly splitting the \$p$pdo

llar sign, p cost among the 242424 of them.
Mathematics
1 answer:
Sladkaya [172]3 years ago
7 0

Answer:

\frac{6000-p}{24}

Step-by-step explanation:

Lets understand the question.

Liam had $250

Cost of gift = p

Total Students = 24 (including Liam)

Each paid:

p/24 (Liam also paid this amount)

So, in terms of Liam, he would have:

250 (already had)

expended p/24 for gift, now he has:

250-\frac{p}{24}\\=\frac{250(24)-p}{24}\\=\frac{6000-p}{24}

This is amount of money Liam had left in terms of p.

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What would be the root of (x^2 + 2)?
Vladimir [108]

Answer:

The roots of the equation are \sqrt{2}i and  -\sqrt{2}i

Step-by-step explanation:

The roots of a quadratic equation y = ax² + bx + c are the values of x at y = 0

∵ y = x² + 2

- To find the roots of it equate y by 0

∴ 0 = x² + 2

- Switch the two sides

∴ x² + 2 = 0

- Subtract 2 from both sides

∴ x² = -2

- Take √  for both sides

∴ x = ± \sqrt{-2}

- There is no square root for negative numbers

∴ There is no real roots for this equation but there are imaginary roots

∵ \sqrt{-1}=i

∴ \sqrt{-2}=\sqrt{2}*\sqrt{-1}

- Substitute \sqrt{-1} by i

∴  \sqrt{-2}=\sqrt{2}*i

∴  \sqrt{-2}=\sqrt{2}i

∴ The roots of the equation are \sqrt{2}i and  -\sqrt{2}i

5 0
3 years ago
Eleanor had a gross income of $2,478.15 during each pay period in 2010 if she got paid monthly how much of her pay was deducted
lina2011 [118]
According to reliable sources online, the FICA rate last 2010 amounted to 6.2%. The amount deducted to Eleanor's pay monthly is calculated by multiplying the monthly pay and the rate. That is,
                                    FICA (monthly) = ($2,478.15)(0.062)
                                                            = $153.636
Multiplying that amount by 12 (since there are 12 months in a year) is equal to $1843.632. Thus, $1843.632 was deducted from Eleanor's pay last 2010 for FICA. 
5 0
3 years ago
Which expressions are equivalent to 1/3 +8d
DaniilM [7]

Answer:

Step-by-step explanation:

Para sacar fracciones equivalentes tienes que multiplicar el numerador y denominador por el mismo numero, por ejemplo varias fracciones equivalentes a 1/3: 2/6, 3/9, 4/12, 5/15.

6 0
3 years ago
An object has a potential energy of 14 J and a mass of 17 kg , how far above the ground is the object? An object moving with a s
victus00 [196]

1. Potential Energy = mgh

h = U_g / (mg) = 14 / (17 * 9.81) = <u>0.084 m above the ground.</u>

2. Kinetic Energy = 1/2 mv^2

m = 2K_e / (v^2) = <u>2.45 kg</u>

3. U_g = mgh = (1200)(9.81)(24) = <u>282528 J</u>

4. U_g = mgh = (478)(9.81)(150) = <u>703377 J</u>

5. U_g = mgh = (100)(9.81)(12.5) = <u>12262.5 J</u>

6. h = U_g / (mg) = 14 / (17 * 9.81) = <u>0.084 m above the ground.</u>

<u />

7. m = U_g / (gh) = 1500 /  (9.81 * 35) = <u>4.37 kg</u>

3 0
3 years ago
If the time period of a vibrating body is 0.4 s, then it’s frequency is
irina1246 [14]

Answer:

2.5

Step-by-step explanation:

6 0
3 years ago
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