Interesting question. Good to know for computer science.
Suppose you have a function like
an = 3x - 2 Try the first couple
a1 = 3(1) - 2
a1 = 3 - 2
a1 = 1
a2 = 3(2) - 2
a2 = 6 - 2
a2 = 4 So each term differs by 3
a2 - a1 = 3
an = a_(n - 1) + 3
a3 = a2 + 3
a3 = 4 + 3
a3 = 7
a4 = a3 + 3
a4 = 7 + 3
a4 = 10
a5 = a4+ 3
a5 = 10 + 3
a5 = 13
I'll do one more and then check it.
a6 = a5 + 3
a6 = 13 + 3
a6 = 16
a6 = 3x -2
a6 = 3*6 - 2
a6 = 18 - 2
a6 = 16 which checks.
So the general formula is
an = a_(n - 1) * k if you were multiplying or
an = a_(n - 1) + k if you were adding. The key thing is that you are working with the previous term.
Answer:
16
Step-by-step explanation:
1/2 ^(-1)=2
8×2=16
Hope that helped.
No
if it has 1 acute angle, then the other 2 must be more than 90 each in other words, the other 2 angles must be over 180
all angles add to 180 no more
so no is answer
Answer:
y = 10x + 6.
Step-by-step explanation:
y = mx + c
Here the slope m = 10 and c = 6 ( the y-intercept)
It's 6 because the point (0, 6) lies on the y-axis (where x = 0).
