Ask question

Ask question

All categories

2 years ago

9

Every day you travel 4 3/4 miles each way to get to school. How many miles do you travel all together to get to and from school

during a typical school week? please include explanation, it would be very helpful

1 answer:

Artyom0805 [142]2 years ago

5 0

Answer:

47.5 miles

Step-by-step explanation:

So, every morning, you travel 4.75 miles to get to school... and another 4.75 miles in the afternoon to return.

So, each day, you travel a total of 9.5 miles (4.75 + 4.75) to go school and back.

On a typical school week, you'll go to school 5 times... so you'll need to travel a total of 47.5 miles (5 * 9.5).

You might be interested in

Answer the following questions using metric conversions.

nydimaria [60]

Answer:

Ok, here is the answers! brainliest pleaseee :D

Step-by-step explanation:

13. - 0.624 kg. (Explanation: 104 grams per one pack of pop-tarts. 104 g x 6 packs of pop-tarts equal 624 grams in total. 624 grams to kilograms is 0.624 kg.)

14. - No. The tablecloth is 155 cm long. It needs to cover a table that is 1.6 meters long. 155 cm to meters is 1.55 meters. The tablecloth is 0.05 to short to cover the table. 1.6 meters - 1.55 meters = 0.005.

15 - Alex's sister rode the farthest. She rode 1,000 meters farther than Alex. 2 kilometers in meters is 2,000 meters. His sister rode 1,000 meters more than that, 3,000.

3 0

3 years ago

The average income, I, in dollars, of a lawyer with an age of x years is modeled with the following function: I = -425x^2 + 45,5

lord [1]

We are given

The average income, I, in dollars is

$I=-425x^2+45500x-650000$

(a)

now, we are given

average income is $275000

so, $I=275000$

now, we can set them equal

and then we can solve for x

$275000=-425x^2+45500x-650000$

$-425x^2+45500x-925000=0$

we will have to use quadratic formula

$x=\frac{-45500+\sqrt{45500^2-4\left(-425\right)\left(-925000\right)}}{2\left(-425\right)}:\quad \frac{-\sqrt{45500^2-1572500000}+45500}{850}$

$x=\frac{-45500-\sqrt{45500^2-4\left(-425\right)\left(-925000\right)}}{2\left(-425\right)}:\quad \frac{\sqrt{45500^2-1572500000}+45500}{850}$

we get

$x=27.28199$

$x=79.776$

we need to find youngest age

It means that we need to choose smallest value

so,

$x=27$ ............Answer

(b)

we are given

x=40

so, we can plug it and find I

$I=-425(40)^2+45500(40)-650000$

$I=490000$ ..............Answer

6 0

3 years ago

There are 3 bags each containing 100 marbles. Bag 1 has 75 red and 25 blue marbles. Bag 2 has 60 red and 40 blue marbles. Bag 3

jekas [21]

Answer:

0.4 ; 0.6125

Step-by-step explanation:

Given the following :

Bag 1 : 75 red ; 25 blue

Bag 2: 60 red ; 40 blue

Bag 3: 45 red ; 55 blue

Probability = (required outcome / Total possible outcomes)

A) since the probability of choosing each bag is equal :

BAG A:

P(choosing bag A) = 1 / total number of bags = 1/3 ; P(choosing blue marble) = number of blue marbles / total number of marbles = 25/100

HENCE, choosing a blue marble from bag A : = (1/3 × 75/100) = 25/300

BAG B:

P(choosing bag B) = 1/3 ;

P(choosing blue marble) = number of blue marbles / total number of marbles = 40/100

HENCE, choosing a blue marble from bag A : = (1/3 × 40/100) = 40/300

BAG C:

P(choosing bag C) = 1/3

P(choosing blue marble) = number of blue marbles / total number of marbles = 55/100

HENCE, choosing a blue marble from bag A : = (1/3 × 55/100) = 55/300

= (25/300) × (40/300) × (55/300) = (25 + 40 + 55)/300 = 120/300 = 0.4

2) What is the probability that the marble is blue when the first bag is chosen with probability 0.5 and other bags with equal probability each?

BAG A:

P(choosing bag A) = 0.5 ; P(choosing blue marble) = number of blue marbles / total number of marbles = 25/100

HENCE, choosing a blue marble from bag A : = (0.5 × 75/100) = (0.5 * 0.75) = 0.375

BAG B:

P(choosing bag B) = (1-0.5) / 2 = 0.25 ;

P(choosing blue marble) = number of blue marbles / total number of marbles = 40/100

HENCE, choosing a blue marble from bag A : = (0.25 × 40/100) = (0.25 × 0.4) = 0.1

BAG C:

P(choosing bag C) = (1 - (0.5+0.25)) = 0.25

P(choosing blue marble) = number of blue marbles / total number of marbles = 55/100

HENCE, choosing a blue marble from bag A : = (0.25 × 55/100) = 0.25 × 0.55 = 0.1375

= 0.1375 + 0.1 + 0.375 = 0.6125

7 0

3 years ago

Select the correct answer. which expression is equivalent to the given expression? assume the denominator does not equal zero. a

Alexxandr [17]

If the denominator does not equal 0, the equivalent expression of $\frac{14x^4y^6}{7x^8y^2}$ is $\frac{2y^{4}}{x^{4}}$ $\frac{x^{10} y^{14}}{729}$

<h3>How to determine the equivalent expression?</h3>

The expression is given as:

$\frac{14x^4y^6}{7x^8y^2}$

Divide 14 by 7

$\frac{14x^4y^6}{7x^8y^2} = \frac{2x^4y^6}{x^8y^2}$

Apply the law of indices

$\frac{14x^4y^6}{7x^8y^2} = \frac{2y^{6-2}}{x^{8-4}}$

Evaluate the differences in the exponents

$\frac{14x^4y^6}{7x^8y^2} = \frac{2y^{4}}{x^{4}}$

Hence, the equivalent expression of $\frac{14x^4y^6}{7x^8y^2}$ is $\frac{2y^{4}}{x^{4}}$

Read more about equivalent expressions at:

brainly.com/question/2972832

#SPJ4

4 0

2 years ago

A 10-yr-old competes in gymnastics. For several competitions, she received the following "All-Around" scores: 35.5, 36.3. 36.6,

Delicious77 [7]

Answer:

The child needs a score of 37.2 to move up to the next level of the competition.

Step-by-step explanation:

The mean is the sum of all scores divided by the number of competions. So

$M = \frac{S}{T}$

In which S is the sum of all her scores and T is the number of competitions.

The child has five competions:

Which means that $T = 5$

She has to get a mean of at least 36.5, so $M = 36.5$

Her scores are: 35.5, 36.3. 36.6, and 36.9. Her last score, i am going to call x. So

$S = 35.5 + 36.3 + 36.6 + 36.9 + x = 145.3 + x$

The child needs a score of _____ to move up to the next level of the competition.

This score is x. So

$M = \frac{S}{T}$

$36.5 = \frac{145.3 + x}{5}$

$145.3 + x = 36.5*5$

$x = 37.2$

3 0

2 years ago