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Alex
3 years ago
6

Divide 5/3 by 1/4 A.3/20 B.5/12 C.4/9 D. 2 2/5

Mathematics
2 answers:
Lynna [10]3 years ago
7 0
\frac{5}{3}:\frac{1}{4}=\frac{5}{3}\cdot\frac{4}{1}=\frac{5\cdot4}{3\cdot1}=\frac{20}{3}=\frac{18+2}{3}=\boxed{6\frac{2}{3}}\\\\from\ comment:\\\\\frac{3}{5}:\frac{1}{4}=\frac{3}{5}\cdot\frac{4}{1}=\frac{3\cdot4}{5\cdot1}=\frac{12}{5}=\frac{10+2}{5}=\boxed{2\frac{2}{5}}\leftarrow answer\ \boxed{\boxed{D}}
salantis [7]3 years ago
3 0
We flip the 2nd fraction and multiply.

5/3 * 4/1 = (5 * 4)/(3 * 1) = 20/3 = 6 2/3

So the correct choice should be 'none of the above' unless you made a mistake in your question.
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3 years ago
The quotient of 3 and the cube<br> of y+2
Rufina [12.5K]

Answer:

  \dfrac{3}{(y+2)^3}

Step-by-step explanation:

Maybe you want this written using math symbols. It will be ...

  \boxed{\dfrac{3}{(y+2)^3}}

3 0
3 years ago
Mr. Stevenson is ordering shirts and hats for his Boy Scout troop. There are 45 scouts in the troop. Hats come in packs of 3, an
luda_lava [24]
9 packs of shirts 15 packs of hats
5 0
4 years ago
Find the volume of the oblique prism. 
coldgirl [10]

Formula for the volume of the oblique prism is:

V=A_{\text{base}}\cdot H.

From the diagram H=12 units and the base is isosceles triangle with lengths of the sides 5, 5 and 6 units.

1. Find the length of the altitude h to the largest side. In isosceles triangle the altitude to the base is also the median, so it divides the base into two equal parts. By the Pythagorean theorem,

h^2+3^2=5^2,\\ h^2=25-9=16,\\ h=4.

2. The area of the base is given by formula

A_{\text{base}}=\dfrac{1}{2} a\cdot h=\dfrac{1}{2}\cdot 6\cdot4=12 sq. un.

Thus, the volum is V=12·12=144 cubic units.

8 0
4 years ago
Max is observing the velocity of a runner at different times. After one hour, the velocity of the runner is 5 km/h. After two ho
Hatshy [7]
You only have two observations to work the equation for the velocity.

You only can assume a linear relation.

Part a.

Calling x the independent variable (time in hours) and y the dependent variable (velocity in km/h) =>

x (time in hours)         y (velocity in km/h)

1                                  5
2                                  3

Now you use the linear relation:

slope: (3 - 5) km/h/ (2 - 1)h = - 2 km/1h^2 = - 2 km/h ^2

Equation:

y - 3 = slope * (x - 2)

=> y - 3 = - 2 ( x - 2)

=> y - 3 = - 2x + 4

=> y = 3 - 2x + 4

=> y = - 2x + 7

that is the slope-intercept form.

the standard form is y + 2x - 7 = 0

part B.

to draw the graph you can make a table with the points for the first four hours:

x (time in hours)            y (velocity in km/h)
                                        -2x + 7

1                                      -2(1) + 7 = 5

2                                      -2(2) + 7 = 3

3                                      -2(3) + 7 = 1

4                                     -2(4) + 7 = - 1

The graph, of course, is a straight line, because we started from that assumption.
7 0
4 years ago
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