45 pages total
3 on last page
45-3=42
there are 42 on the rest of the pages
on each page, there are 2 more pages in album than then stamps on pages
amount of stamps on pages with equal number of stamps is
A=numberofpgest times number of stamps on pages
number of pages=p
number of stamps per papge=s
a=ps
2 more pages than stamps on pages
p=2+s
total number of stamps per page is s=(45-3)/(p-1)
(what I did is I first got rid of number of stamps on last page, then got rid of the last page)
P=2+s
s=(45-3)/(2+s-1)
s=42/(s+1)
times s+1 both sides
s^2+s=42
minus 42
s^2+s-42=0
factor
(s-6)(s+7)=0
set equal to zero
s-6=0
s=6
s+7=0
s=-7, false, no negative stamps
6 stamps per page
sub
p=2+s
p=2+6
p=8
8 pages
check
last page is 3 so 8-1=7 page left
7*6=42
3+42=45
correct
there are
8 pages in the album
6 stamps per page
Answer: 256 units squared
Step-by-step explanation:
So basically you times 4*4*2*8.
4 is the only factor common among all terms
Hi there!
When we have an equation standard form...

...the formula of the discriminant is
D = b^2 - 4ac
When
D > 0 we have two real solutions
D = 0 we have one real solutions
D < 0 we don't have real solutions
1.) Find the value of the discriminant and the the number of real solutions of
x^2-8x+7=0
Plug in the values from the equation into the formula of the discriminant

D > 0 and therefore we have two real solutions.
2.) Find the value of the discriminant and the number of real solutions of
2x^2+4x+2=0
Again, plug in the values from the equation into the formula of the discriminant.

D = 0 and therefore we have one real solution.
~ Hope this helps you.