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Vitek1552 [10]
3 years ago
15

Whats the center and radius of (x+3)^2+(y-5)^2=64

Mathematics
1 answer:
Alexandra [31]3 years ago
5 0

Answer:

The answer to your question is Center = (-3, 5)  radius = 8

Step-by-step explanation:

Data

                (x + 3)²  +  (y - 5)² = 64

Process

Because of the characteristics of the equation, we conclude that it is a circle.

Standard form of a circle:

              (x - h)² + (y - k)² = r²

In this form of the equation, the center has coordinates (h, k), just change the signs.

And to get the radius, just get the square root of r²

h = -3

k = 5

r = 8

Center = (-3, 5)

radius = 8

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Anna [14]

Answer:

12x + 2

Step-by-step explanation:

To find what the expression equals, you can collect like terms. This means to do the operations (add or subtract) the numbers that have the same variables.

(8x + 5) + (4x - 3)        Remove brackets to add a binomial (2-term brackets)

= 8x + 5 + 4x - 3        Collect like terms

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Therefore (8x + 5) + (4x - 3) is equal to 12x + 2.

If you want, you can also find another equal expression by factoring. Since "12x" and "2" are both divisible by the factor 2, you can <em>take it out</em> and put the other numbers in a bracket.

12x + 2

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Step-by-step explanation:

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Answer:

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Step-by-step explanation:

The question requires that the equation should be in the slope-intercept form y = m \, x + c. The m and c in this equation are constants. In particular:

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The question states that the slope of this line is (-3). Therefore, m = -3. Thus, the equation for this line should be in the form y = (-3)\, x + c.

The value of constant c could be found using the other piece of information: the point (3,\, 1) is in this line. In other words, the solution \text{$x = 3$ and $y = 1$} should satisfy the equation y = (-3)\, x + c.

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