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Vitek1552 [10]
3 years ago
15

Whats the center and radius of (x+3)^2+(y-5)^2=64

Mathematics
1 answer:
Alexandra [31]3 years ago
5 0

Answer:

The answer to your question is Center = (-3, 5)  radius = 8

Step-by-step explanation:

Data

                (x + 3)²  +  (y - 5)² = 64

Process

Because of the characteristics of the equation, we conclude that it is a circle.

Standard form of a circle:

              (x - h)² + (y - k)² = r²

In this form of the equation, the center has coordinates (h, k), just change the signs.

And to get the radius, just get the square root of r²

h = -3

k = 5

r = 8

Center = (-3, 5)

radius = 8

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"(b) use part (a) to find a power series for f(x) = 1 (4 + x)3 ."
Firdavs [7]
Assuming

f(x)=\dfrac1{(4+x)^3}

Recall that for |x|,

\displaystyle\sum_{n\ge0}x^n=\frac1{1-x}

Denote the above by s(x). Then

s'(x)=\displaystyle\sum_{n\ge1}nx^{n-1}=\frac1{(1-x)^2}
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Now,

\dfrac1{(4+x)^3}=\dfrac1{4^3}\dfrac1{\left(1-\left(-\frac x4\right)\right)^3}=\dfrac1{2^7}\dfrac2{\left(1-\left(-\frac x4\right)\right)^3}

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3 years ago
PLEASE HELP D:
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Answer:

  • C. 40 ft²

Step-by-step explanation:

<u>Triangle area formula:</u>

  • A = bh/2, where b- base, h- height

<u>We have:</u>

  • b = 8 ft, h = 10 ft

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