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cluponka [151]
3 years ago
12

WILL GIVE BRAINLIEST​

Mathematics
2 answers:
Goshia [24]3 years ago
7 0

Answer:

B because thats were they both cross

Step-by-step explanation:

Lisa [10]3 years ago
3 0
The answer to your equation is B
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Solve for the variable <br><br><br> u^2 + 2 = 11
stira [4]

Answer:

There are two roots:  -3 and 3

Step-by-step explanation:

Combine the like terms first.  We get u^2 = 9.

There are two roots:  -3 and 3.

8 0
3 years ago
Determine whether the triangles are similar? If not explain why.
amm1812
They are similar, though not congruent. They have some differences between angles.
(All this Web playing has paid off...)
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3 0
3 years ago
How many blocks 1 inch on each edge would it take to fill a shoe box that is 12 inches long, 6 inches wide, and 5 inches tall?
ICE Princess25 [194]
First find the volume of the block(s):
A=s^3
s=side length

A=1^3
A=1 cubic inch

Next, find the volume of the shoe box:
12*6*5 
360 cubic inches

Finally, divide the volume of the larger box by the volume of the block to get how many blocks will fit:

360/1 = 360 blocks
4 0
3 years ago
Read 2 more answers
The figure is a parallelogram.one diagonal measures 28 units. Is the figure a rectangle? Explain
guajiro [1.7K]

Answer:

The parallelogram is not rectangle because the sides of the parallelogram do not meet at right angles.

Step-by-step explanation:

Given the parallelogram with sides 20 and 21 units with diagonal length 28 units.

we have to tell it is a rectangle or not.

The given parallelogram is rectangle if the angle at vertices are of 90° i.e the two triangle formed must be right angles i.e it  must satisfy Pythagoras theorem

28^{2}=20^{2}+21^{2}

784=400+441=881

Not verified

∴ The sides of the parallelogram do not meet at right angles.

Hence, the parallelogram is not rectangle because the sides of the parallelogram do not meet at right angles.

Hope it helps

Mark as brainliest

5 0
3 years ago
Hi I'm a girl and if anyone need help come to me cause I'm here and I know every thing and I'm nice:)
alexira [117]
Uhmm ok thank uuuuuu
3 0
3 years ago
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